Wonderful! You've given us a veritable wealth of data to play with,
including the size of the guest list, the meat ration for each turkey,
and a useful metric to English conversion.

Now, if you had only told us something about the unit price of
the birds, we might even be able to answer the question that
you actually asked.

4 0

3 years ago

In a pile of 55 coins made of nickels and dimes totaling $3.90 how many of each coin are there

tigry1 [53]

There are 5 pennies in a nickel, and 10 pennies in a dime. Now in $3.90 there are 390 pennies.

n = number of nickels in the pile

d = number of dimes in the pile

we know the pile has 55 coins, therefore whatever "n" and "d" are, we know that n + d = 55.

now, "n" is how many nickel coins are there, how many pennies is it in total? well, 5 pennies to a nickel, for "n" nickels, will then be 5(n) or 5n.

and "d" is how many dime coins are there, so therefore in "d" coins, there are 10(d) pennies, or 10d.

we also know the total amount of pennies is 390, therefore 5n + 10d = 390.

$\bf \begin{cases}
n+d=55\implies \boxed{n}=55-d\\
5n+10d=390\\
-------------\\
5\left(\boxed{55-d} \right)+10d=390
\end{cases}
\\\\\\
275-5d+10d=390\implies 5d=115\implies d=\cfrac{115}{5}\implies d=23$

how many nickel coins are there anyway? well, n = 55 - d.

8 0

3 years ago