Find the sum of numbers from m to n

Select the ordered pairs that are solutions to the inequality 2x-3y greater than or equal to 12

Dima020 [189]

Just rank every pair of numbers for example:
The first one is: 1,-3.
2•1-3•-3>12
2+9>12
11>12
That's Incorrect. The first pair of numbers doesn't match the inequality.
Now do the same thing to all the other pairs of numbers.

3 0

3 years ago

Read 2 more answers

HELP ME PLEASE FOR BRAINLIEST!!!!

Brilliant_brown [7]

I think it is 10.

hope this helps!!! :D

3 0

3 years ago

-A library currently has 125 audiobooks. The library plans to

Agata [3.3K]

Answer: 1 the 2 of 3 and 5a 5 to 6 in 8 is 9 be 9 that 9 was 10 he 11 for 11 it 14 with 15 ... 42 him 43 been 44 has 44 more 45 if 45 no 47 out 48 do 49 so 50 can 50 what ... right 143 might 146 came 146 off 147 find 148 states 149 since 149 used ... 1383 circle 1383 ought 1384 garden 1386 library 1390 accuse 1390

Step-by-step explanation:

5 0

3 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

3 years ago

A k out of n system is one in which there is a group of n components, and the system will function if at least k of the componen

Solnce55 [7]

Answer:

0.9606 = 96.06% probability that the system will function tomorrow

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works, or it does not. Components are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$