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Travka [436]
3 years ago
13

you have $2.50. Each sugar free gumball in a gumball machine cost $0.25. Write and solve an inequality that represents the numbe

r of gumballs you can buy.
Mathematics
1 answer:
Crank3 years ago
8 0
2.50/0.25, so this will equal 10.
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Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0
3 years ago
Skylar is answering the following math problem: The value of an investment decreased by 10%. The original amount of the investme
Alona [7]

Answer:

The given parameters of the investment are;

The rate of decrease of the investment, r = -10%

The original amount of the investment, P = $75.00

Let 'A' represent the final answer (value of the investment) after the decrease in the investment, 'r', is applied, we have;

The algebraic equation that can be used to arrive at the final answer, 'A', is given as follows;

A = P + r·P

Therefore by substituting the given values, we have;

A = $75.00 + (-10/100) × $75.00 = $75.00 - 0.1 × $75.00 = $75.00 - $7.50

A = $75.00 - $7.50 = $67.50

The final amount or answer, A = $67.50

Step-by-step explanation:

3 0
3 years ago
If 32 % of a is 1.12 then what is the value of a?
alukav5142 [94]

Answer:

4.5 is the value of A

Step-by-step explanation:

do it doing part/whole and cross crossing :)

32/100 because it’s a percentage and 1.12/x. 1.12 times 100 to get 112, and then 32 times x = 32x. your equation right now is 32x = 112, bur we want to get rid of that x, so we are going to divide 112/32 to get the whole of 3.5 for the value of A.

7 0
3 years ago
ASAP PLEASE HELP!!!
Mariulka [41]

Z score = (x -mean) /  standard deviation.

For this problem X = 50 cm.

Z-score = (50 - 49.2) / 1.8

Z score = 0.8 / 1.8

Z score = 0.44

Look up 0.44 on a z-score table.

0.44 = 0.6700

0.67 x 100 = 67% will be 50 cm or longer.

8 0
3 years ago
Machine produces 1000 bowling pins per hour each valued at $8.37 what is the total value of the PMs produced in one hour
Komok [63]
Number of pins produced per hour is 1000
value of each pin is $8.37
total value of pins produced= 1000×$8.37
=$8370
8 0
3 years ago
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