Since you already know the values of a and b, all you have to do is split the problem into little parts and plug everything into its spot. AB would equal 1(5) which is 5. Athens 0.5b would equal, 0.5(5) to equal 2.5. So now your equation is 5-2.5+1/2 which equals 3.
Answer:
x^2+y^2 = 3^2
Step-by-step explanation:
We need to eliminate the parameter t
Given:
x = 3 cos t
y = 3 sin t
Squaring the above both equations
(x)^2=(3 cos t)^2
(y)^2 =(3 sin t)^2
x^2 = 3^2 cos^2t
y^2=3^2 sin^2t
Now adding both equations
x^2+y^2=3^2 cos^2t+3^2 sin^2t
Taking 3^2 common
x^2+y^2=3^2 (cos^2t+sin^2t)
We know that cos^2t+sin^2t = 1
so, putting the value
x^2+y^2=3^2(1)
x^2+y^2 = 3^2
Hence the parameter t is eliminated.
Answer:
Domain: all reals
Range: 4 ≤y <∞
Step-by-step explanation:
The domain is the possible input values(x)
From the arrows at the left and right ends on the graph, the inputs can be all reals
The range is the possible output values (y)
Y goes from 4 to infinity
4 ≤y <∞
Answer:
Step-by-step explanation:
h + 4 ≤ 20
Subtract 4 from both sides.
h ≤ 20 − 4
Subtract 4 from 20 to get 16.
Hope it helps and have a great day! =D
~sunshine~
The price of one bag of popcorn is $3.75
Step-by-step explanation:
Let,
x represent the cost of a bag of popcorn
y represent the cost of a drink.
According to given statement;
4x+12y=30 Eqn 1
x+6y=11.25 Eqn 2
Multplying Eqn 2 by 2
Subtracting Eqn 3 from Eqn 1
Dividing both sides by 2
4x+12y=30 and x+6y=11.25 can be used to find the price of one bag of popcorn and the price of one drink.
The price of one bag of popcorn is $3.75
Keywords: linear equation, elimination method
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