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BaLLatris [955]
3 years ago
5

What would the answer be?

Mathematics
1 answer:
melomori [17]3 years ago
4 0

Answer:

The answer would be the bottom one (please give branliest)

15c = 183.75

Step-by-step explanation:

The individual cost per ice skating lesson can be found by dividing the total by the amount she got

183.75 / 15 = 12.25

The second one is correct because c = 12.25 and 15 X 12.25 = 183.75

The first one is wrong because 12.25 / 15 is not 183.75

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The answer is B because area it's length times width and 5 times 3 is 15
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Angle 1 and angle 4 are congruent because all vertical angles are congruent. Angle 1 and angle 5 are congruent because corresponding angles are congruent. Idk the rest.

Step-by-step explanation:

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3 years ago
Two rental car companies are running specials this month. At Johnson's Rentals, customers will pay $50 to rent a mid-sized car f
murzikaleks [220]

Answer:

If we rent the same car from both companies it would take 8 days

Step-by-step explanation:

Johnson's   50+2x

Martinez     30+4x

7 0
3 years ago
The following value 1.23456789 x 10-6 <br>what is a answer?​
Amiraneli [1.4K]

Answer 1:

<em>1.23456789 × (10-6) = 4.93827156</em>

Answer 2:

<em>(1.23456789 × 10) - 6 = 6.3456789</em>

Answer 3:

<em>1.23456789 × </em>10^{-6} <em>= 0.000000123456789</em>

<em>Hope this helped! :)</em>

4 0
2 years ago
Show all worked identify the asymptotes and state the end behavior of the function F(x)=6x over x-36
astraxan [27]

Solution

Asymptote:

Vertical Asymptote

- The vertical asymptotes of a rational function are determined by the denominator expression.

- The expression given is:

f(x)=\frac{6x}{x-36}

- The denominator of (x- 36) determines the asymptote line.

- The vertical asymptote defines where the rational function isundefined. Iin order for a rational function to be undefined, its denominator must be zero.

- Thus, we can say:

\begin{gathered} x-36=0 \\ Add\text{ 36 to both sides} \\  \\ \therefore x=36 \end{gathered}

- Thus, the vertical asymptote is

x=36

Horizontal Asymptote:

- The horizontal asymptote exists in two cases:

1. When the highest degree of the numerator is less han the degree of the demnominator. In this case, the horizontal asymptote is y = 0

2. When the highest degee sof the numerator and tdenominator are the same. In this case, the horizontal asymptote is

\begin{gathered} y=\frac{N}{D} \\ where, \\ N=\text{ Coefficient of the highest degree of the numerator} \\ D=\text{ Coefficient of the highest degree of the denominator} \end{gathered}

- For our question, we can see that the highest degrees of the numerator and denominator are the same. Thus, we have the Horizontal Asymptote to be:

y=\frac{6}{1}=6

End behavior:

- The end behavior is examining the y-values of the function as x tendsto negative and positive infinity.

- Thus, we have that:

\begin{gathered} f(x)=\frac{6x}{x-36} \\  \\ \text{ Divide top and bottom by }x \\ f(x)=\frac{6x}{x-36}\times\frac{x}{x} \\  \\ f(x)=\frac{\frac{6x}{x}}{\frac{x-36}{x}}=\frac{6}{1-\frac{36}{x}} \\  \\ As\text{ }x\to-\infty \\ f(-\infty)=\frac{6}{1-\frac{36}{-\infty}}=\frac{6}{1+\frac{36}{\infty}}=\frac{6}{1+0}=6 \\  \\ \text{ Thus, we can say: }x\to-\infty,f(x)\to6 \\  \\ Also, \\ As\text{  }x\to\infty \\ f(\infty)=\frac{6}{1-\frac{36}{\infty}}=\frac{6}{1-0}=6 \\  \\ \text{ Thus, we can also say: }x\to\infty,f(x)\to6 \end{gathered}

Final Answers

Asymptotes:

\begin{gathered} \text{ Vertical:} \\ x=36 \\  \\ \text{ Horizontal:} \\ y=6 \end{gathered}

End behavior:

\begin{gathered} As\text{  }x\to-\infty,f(x)\to6 \\  \\ As\text{  }x\to\infty,f(x)\to6 \end{gathered}

7 0
1 year ago
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