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tigry1 [53]
3 years ago
12

Write the equation for the sine function shown below

Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0
Try this explanation+solution:
1. According to the given graph it is possible to define A - amplitude and B - frequency of this function, then to substitute them to its equation.
2. A=5 (max. and min. values for vertical); B=2 (two periods in the length 2π).
3. answer: y=5sin2x.
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- The four-digit number 1210 has an interesting property.
vampirchik [111]

Answer:

ABCDEFG = 3211000

Step-by-step explanation:

A counts the number of zeroes, and there are 3 zeroes (E, F, G), so A = 3.B counts the number of ones, and there are 2 ones (C, D), so B = 2.C counts the number of twos, and there is 1 two (B), so C = 1.D counts the number of threes, and there is 1 three (A), so D = 1.There is no four, five, six in, so E, F, G are all zeroes.

5 0
2 years ago
.45, .75, .5, .625 in greatest to least
GREYUIT [131]

Answer:

0.75, 0.625, 0.5, 0.45

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
At what rate per annum ci will RS 2000 amount to RS 2315.35 in 3 years
Mashutka [201]

<u>ANSWER: </u>

Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%

<u>SOLUTION: </u>

Given,  

P = RS 2000

C.I = RS 2315.35

T = 3 years

We need to find the rate per annum. i.e. R = ?

We know that,  

When interest is compound Annually:

Amount $=\mathrm{P}\left(1+\frac{\mathrm{R}}{100}\right)^{n}$

Where p = principal amount

r = rate of interest

n = number of years

$2315.35=2000 \times\left(1+\frac{R}{100}\right)^{3}$

$\left(1+\frac{R}{100}\right)^{3}=\frac{2315.35}{2000}$

$\left(1+\frac{R}{100}\right)^{3}=1.157$

$1+\frac{R}{100}=\sqrt[3]{1.157}$

$1+\frac{R}{100}=1.0500$

$\frac{R}{100}=1.05-1$

$\frac{R}{100}=0.05$

R = 5%

Hence, rate per annum is 5 percent.

3 0
3 years ago
the ratio of red cars to blue cars in a parking lot was 5 : 3. if there were 40 cars, how much blue cars were there​
maria [59]

Answer: 24

Step-by-step explanation:

6 0
3 years ago
Help me pls!!
tresset_1 [31]

(a) Truck carries 90 gallons of diesel fuel to 660 miles.

So, 1 gallon of diesel fuel to 660/90 = 22/3 miles.

30 gallons of diesel fuel to  = 220 miles.

Hence, if x-axis represents the number of miles and y-axis represents the number of gallons, then, (660, 90) and (220, 30) are points on the graph.

Join (660, 90) and (220, 30), we get the graph of a line.

Note that (0, 0) is also a point on the line.

Equation of the line is .

(b) x represents the number of miles. Therefore, the possible values for x is the closed interval [0, 660].

Hence, the domain of the function is [0, 660].

(c) Origin represents that the truck is not moving and there is no diesel fuel loaded in the truck.

7 0
3 years ago
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