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tigry1 [53]
2 years ago
12

Write the equation for the sine function shown below

Mathematics
1 answer:
liubo4ka [24]2 years ago
6 0
Try this explanation+solution:
1. According to the given graph it is possible to define A - amplitude and B - frequency of this function, then to substitute them to its equation.
2. A=5 (max. and min. values for vertical); B=2 (two periods in the length 2π).
3. answer: y=5sin2x.
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There are 63 students in a speech contest.Yesterday 1/3 gave a speech and today 2/3 of the remaining students gave their speech.
Paraphin [41]

Hey!

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Solution:

Find 1/3 of 63.

63 / 3 = 21

21 students gave a speech today.

63 - 21 = 42

Find 2/3 of 42.

42 / 3 = 14

14 x 2 = 28

28 of the remaining students gave their speeches.

42 - 28 = 14

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Answer:

14 students haven't given their speeches!

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Hope This Helped! Good Luck!

7 0
2 years ago
Which point on the grid have they not explored?
aniked [119]

Answer:

(-3, 1)

Step-by-step explanation:

4 0
2 years ago
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Which point is not on the graph of the function y = x + 5?
OleMash [197]

Answer:

(10, 5 )

Step-by-step explanation:

To determine which points lie on the graph or not.

Substitute the x- coordinate of the point into the equation and if the value agrees with the y- coordinate of the point then the point is on the graph.

(2, 7 )

y = 2 + 5 = 7 ← True thus point is on the graph

(6, 11 )

y = 6 + 5 = 11 ← True thus point is on the graph

(220, 225 )

y = 220 + 5 = 225 ← True thus point is on the graph

(10, 5 )

y = 10 + 5 = 15 ≠ 5 ← Point is not on the graph

8 0
3 years ago
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What is the area of this shape?
alex41 [277]

Answer:

236.55 (Rounded to two decimal places)

Step-by-step explanation:

Area of the rectangle:

12 x 15 = 180

Area of semicircle:

π6^2/2 = 56.54866776...

Total area:

180 + 56.54866776...

= 236.55

5 0
2 years ago
Write an equation of the circle given its center and radius
lara [203]

Answer:

16=(x-0)^{2}+(x-0)^{2}

Step-by-step explanation:

In writing equations for circles with the center and radius given we follow the formula r^{2}=(x-h)^{2}+(y-k)^{2}.

The value of h and k are the center values of (0,0).

So we have:

h = 0

k = 0

r = 4

Now let's plug these values into our formula.

4^{2}=(x-h)^{2}+(x-k)^{2}

4^{2}=(x-0)^{2}+(x-0)^{2}

16=(x-0)^{2}+(x-0)^{2}

7 0
3 years ago
Read 2 more answers
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