(x - 4)(2x + 3)
Using foil:
2x^2 + 3x - 8x - 12
Simplify.
2x^2 - 5x - 12 is the product after using FOIL.
Let's complete the square
f(x) = x^2 + 6x + 8
y = x^2 + 6x + 8
y-8 = x^2 + 6x
y-8+9 = x^2+6x+9 .... see note below
y+1 = (x+3)^2
y = (x+3)^2-1
note: I added 9 to both sides due to taking half of the 6, and then squaring that result.
We'll restrict x such that
to ensure that this function is one-to-one.
Now we need to swap x and y, and solve for y to get the inverse
y = (x+3)^2 - 1
x = (y+3)^2 - 1
x+1 = (y+3)^2
(y+3)^2 = x+1
y+3 = sqrt(x+1)
y = sqrt(x+1)-3
g(x) = sqrt(x+1)-3 is the inverse
The graph is shown below. The original function is in red. The inverse is in blue. The inverse is the result of reflecting the red curve over the dashed line y = x. So this explains why x and y swap places. Consequently, the domain and range also swap as well.
They have different numbers on a number line
Answer: The functions have the same initial value
Step-by-step explanation: I say this because "Tour 1" is a linear funtion. I subtracted 45 from 55 and got 10, this happened for all the numbers on the table. On the other hand, When observing the graph it shows the initial point between 40 and 30. I estimated and got 35. When I went to check my answer, I subtracted 35 from 45 and got 10. Therefore, 35 is the initial value for both the graph and the chart.