We define the probability of a particular event occurring as:

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.
Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:
(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5
So, we have

probability of rolling at least one 5.
Answer:
amt. the shop spends on 40 pairs
= $11 × 40
= $440
amt. paid extra (due to fixed cost) per pair
= ($450 - $440) ÷ 40
= $0.25
amt. per pair to break even
= $11 + $0.25
= $11.25
Answer:
I am not sure but if p/8=0 then it is correct
hope it helps! :D
Answers:
1. There are rivets on the belts.
2. Extra information given in the problem:
a. He has 9 buckles.
b. He has 22 rivets left over.
Solution:
1. Total rivets on the belts=(12 rivets/belt)(4 belts)+(15 rivets/belt)(2 belts)
Total rivets on the belts=48 rivets+30 rivets
Total rivets on the belts=78 rivets
2. The extra information given in the problem is the information that we didn't use to solve it. In this case:
a. He has 9 buckles.
b. He has 22 rivets left over.
Answer:
Yeah with that type of problem
Step-by-step explanation:
You aint getting answered for the next 4 hours <3