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3 years ago

3/8d+3/4 factor out coefficient

Mathematics

1 answer:

Orlov [11]3 years ago

5 0

Coefficient is a number next to the variable so the coefficient of this expression is 3/8

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The formula y - y1 = m(x - x1) is the point-slope form of the equation of a line where m is the slope of the line and (x, y) and

a_sh-v [17]

Answer:

The slope of a line that includes the points (4, -2) and (5, 0) is 2

Step-by-step explanation:

You know that the formula y - y1 = m(x - x1) is the point-slope form of the equation of a line where m is the slope of a line.

The line must include the points (4, -2) and (5, 0). So, being:

(x,y)= (4,-2)
(x1,y1)= (5, 0)

and replacing in the point-slope form of the equation of a line:

-2-0=m(4-5)

You solve the equation for m and get:

-2=m*(-1)

$m=\frac{-2}{-1}$

m=2

The slope of a line that includes the points (4, -2) and (5, 0) is 2

5 0

2 years ago

Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 . C=

Ganezh [65]

Answer:

$y(1+x)+x-5\ln xy=C$

Step-by-step explanation:

Consider the given differential equation is

$(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1$

$(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y$

$(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx$

Taking all variables on right sides.

$(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0$

$(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0$

Let as assume,

$M=-\frac{5}{x}+1+y$ and $N=1-\frac{5}{y}+x$

Find partial derivatives $\frac{\partial M}{\partial y}$ and $\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$ and $\frac{\partial N}{\partial x}=1$

Since $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ , therefore the given differential equation is exact.

The solution of the exact differential equation is

$\int Mdx+\int N(\text{without x)}dy=C$

$\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C$

$yx-5\ln x+x+y-5\ln y=C$

$y+x+xy-5\ln x-5\ln y=C$

$y(1+x)+x-5(\ln x+\ln y)=C$

$y(1+x)+x-5\ln xy=C$

7 0

3 years ago

List all the pairs of integers with a product of 36. then find the pair whose sum is 20

RoseWind [281]

This is an excellent practice for the solution of quadratic equations.

1*36=36 => (1,36)
2*18=36 => (2,18)
3*12=36 => (3,12)
4*9=36 => (4,9)
6*6=36 => (6,6)
9*4=36 => (9,4)
12*3=36 => (12,3)
18*2=36 => (18,2)
36*1=36 => (36,1)

We can see that the sum decreases until the two factors are close (or equal) and then increases again.

The pair of integers with a sum of 20 is therefore (2,18) or (18,2).

4 0

3 years ago

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ArbitrLikvidat [17]

Eduardo is packing 12 pairs of mismatched socks for his trip.

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2 years ago

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Neporo4naja [7]

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