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3 years ago

How do I write the sum of 6x and 2x is at least 39 ?

Mathematics

1 answer:

tatiyna3 years ago

5 0

<h2>Put x = $\dfrac{39}{8}$ I write the sum of 6x and 2x is at least 39 .</h2>

Step-by-step explanation:

We have,,

6x and 2x

To find, the value of x = ?

According to question,

The sum of 6x and 2x is at least 39

∴ 6x + 2x = 39

⇒ 8x = 39

⇒ x = $\dfrac{39}{8}$

∴ The value of x = $\dfrac{39}{8}$

Thus, put x = $\dfrac{39}{8}$ I write the sum of 6x and 2x is at least 39 .

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Step-by-step explanation:

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2 years ago

An expression is shown below: 2x3y + 18xy − 10x2y − 90y Part A: Rewrite the expression by factoring out the greatest common fact

SCORPION-xisa [38]

Answer:

Part A : 2y( x³ + 9x - 5x² - 45 ), Part B : 2y( x - 5 )( x² + 9 )

Step-by-step explanation:

Part A : Let's break every term down here to their " prime factors ", and see what is common among them,

2x³y + 18xy − 10x²y − 90y -

2x³y = 2 $*$ x³ $*$ y,

18xy = 2 $*$ 3 $*$ 3 $*$ x $*$ y,

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− 90y = 2 $*$ - 5 $*$ 3 $*$ 3 $*$ y

The terms common among each term are 2 and y. Therefore, the GCF ( greatest common factor ) is 2x. Let's now factor the expression using this value.

2y( x³ + 9x - 5x² - 45 )

Part B : Let's simply factor this entire expression. Of course starting with the " factored " expression : 2y( x³ + 9x - 5x² - 45 ),

$2y\left(x^3+9x-5x^2-45\right)$ - Factor out " $(x^3+9x-5x^2-45\right))$ " by grouping,

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$\left(x-5\right)\left(x^2+9\right)$ - And our solution is thus 2y( x - 5 )( x² + 9 )

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