Let
x-----------> first <span>odd integer
x+2--------> second consecutive odd integer
x+4-------> third consecutive odd integer

we know that
(x+4)</span>²=15+x²+(x+2)²-------> x²+8x+16=15+x²+x²+4x+4
x²+8x+16=19+2x²+4x-------> x²-4x+3
x²-4x+3=0

using a graph tool----------> to calculate the quadratic equation
see the attached figure
the solution is
x=1
x=3

the answer is
the first odd integer x is 1
the second consecutive odd integer x+2 is 3
the third consecutive odd integer x+4 is 5

7 0

3 years ago

53- (-32) what is the answer?

shutvik [7]

Answer:

Step-by-step explanation:

Here is a tip: When you have something that looks like this - ( - , turn it into a plus sign. It looks kind of like a plus sign anyway. So if you have 53- (-32), turn it into 53 + 32. Does that make sense?

So 53 + 32 = 85.

Another tip to do it in your head, is to do 50 + 30 = 80, then do 3 + 2 = 5, and add them. It's easier than trying to juggle the odd numbers. :)

3 0

3 years ago