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lukranit [14]
4 years ago
7

A man loses 20 percent by selling an article for 11. What was the cost price of the article

Mathematics
1 answer:
dlinn [17]4 years ago
3 0

Answer:

11.2

Step-by-step explanation:

Because

x-20%=11

x-0.2=11

x=11.2

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stira [4]
Well....if the triangle shape stays the same then the angle stays the same even if its enlarged in size. It will stay the same because you didn't change the way the shpae looks like, it is just zoomed in.

Answer: The angle measurements stay the same when the figure is enlarged or reduced
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4 years ago
Triangle ABC is similar to triangle DEF. Find the value of side length DE. Side length DE is cm.
Art [367]

Answer:

??? I can't see the picture

Step-by-step explanation:

5 0
3 years ago
Find the exponential function that satisfies the given conditions: Initial value = 64, decreasing at a rate of 0.5% per week
mrs_skeptik [129]

Answer:

Step-by-step explanation:

An exponential function is of the form

y=ab^x

where a is the initial value and b is the growth/decay rate.  Our initial value is 64.  That's easy to plug in.  It goes in for a.  So the first choice is out.  Considering b now...

If the rate is decreasing at .5% per week, this means it still retains a rate of

100% - .5% = 99.5%

which is .995 in decimal form.

b is a rate of decay when it is greater than 0 but less than 1; b is a growth rate when it is greater than 1.   .995 is less than 1 so it is a rate of decay.  The exponential function is, in terms of t,

f(t) = 64(.995)^t

4 0
3 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
The point is located three units to the left of the y-axis<br> and four units above the x-axis.
padilas [110]
(-3,4). Thats the answer.
6 0
3 years ago
Read 2 more answers
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