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3 years ago

What is the length of MN? 52 units 6 units 4 units 10 units PLEASE HELP

Mathematics

1 answer:

Sladkaya [172]3 years ago

6 0

Answer:

√52 units

Step-by-step explanation:

The segment MN is the hypotenuse of a right triangle that is 6 units wide and 4 units high. The Pythagorean theorem tells you its length is ...

MN = √(6² +4²) = √(36 +16)

MN = √52

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Brenda throws a dart at this square-shaped target: Part A: Is the probability of hitting the black circle inside the target clos

Masteriza [31]

Either way. The probability of hitting the circle is:

P(C)=Area of circle divided by area of square

P(W)=(area of square minus area of circle divided by area of square

P(C)=(πr^2)/s^2

P(W)=(s^2-πr^2)/s^2

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Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:

P(inside circle)=π/121 (≈0.0259 or 2.6%)

P(outside circel)=(121-π)/121 (≈0.9744 or 97.4%)

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3 years ago

An army base in the desert is located at the origin, O of an x-y coordinate system. A soldier at point P needs to determine his

Nutka1998 [239]

Answer/step-by-step explanation

The soldier at point P lie on a parabola because he determined his position and distances from towns A and B through measurement of the difference in timing (phase) of radio signals received from the two towns.

This analysis of the signal time difference gives the difference in distance of the soldier at P, from the towns.

This process is known as hyperbolic navigation.

These distances of point P from towns A and B is estimated by the soldier at point P, by measuring the delay localizes the receiver to a hyperbolic line on a chart.

Two hyperbolic lines will be drawn by taking timing measurements from the

towns A and B .

Point P will be at the intersection of the lines.

These distances of point P(The soldier's positions) from town A and town B were determined using the timing of the signals received from the two towns, due to the fact that point P was on a certain hyperbola.

8 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

ehidna [41]

Answer: 1) 0.10

2) 0.60

3) 0.20

4) 0.10

<u>Step-by-step explanation:</u>

The total frequency is 20+120+40+20 = 200. This means they ran the experiment 200 times. The probability distribution is calculated by the satisfactory number of outcomes (frequency) divided by the total number of experiments/outcomes (total frequency):

$\begin{array}{c|c||lc}\underline{x}&\underline{f}&\underline{f\div 200}&\underline{\text{Probability Distribution}}\\1&20&20\div200=&0.10\\2&120&120\div 200=&0.60\\3&40&40\div 200=&0.20\\4&20&20\div 200=&0.10\end{array}\right]$

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3 years ago

In a translation, the line segments that connect each point on the preimage to the corresponding point on the image are not only

makvit [3.9K]

Parallel because congruency and parallelism is somehow similar and that word fits in perfectly

5 0

3 years ago

Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = x − ln 8x, [1/2, 2]

insens350 [35]

The given function is
f(x) = x - ln(8x), on the interval [1/2, 2].

The derivative of f is
f'(x) = 1 - 1/x
The second derivative is
f''(x) = 1/x²

A local maximum or minimum occurs when f'(x) = 0.
That is,
1 - 1/x = 0 => 1/x = 1 => x =1.
When x = 1, f'' = 1 (positive).
Therefore f(x) is minimum when x=1.
The minimum value is
f(1) = 1 - ln(8) = -1.079

The maximum value of f occurs either at x = 1/2 or at x = 2.
f(1/2) = 1/2 - ln(4) = -0.886
f(2) = 2 - ln(16) = -0.773
The maximum value of f is
f(2) = 2 - ln(16) = -0.773
A graph of f(x) confirms the results.

Answer:
Minimum value = 1 - ln(8)
Maximum value = 2 - ln(16)

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3 years ago