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3 years ago

Which equations model exponential growth?

2 answers:

8 0

P = A(1+r)^x

where P is the population at time x
A is the initial population and r is the growth/decay rate. Growth will be +positive r number added to the 1. Where as decay subtracts r. So any answers that are > than 1 which is answers A and B.

Gnesinka [82]3 years ago

3 0

Answer:

y=2(0.20)* y=0.55(0.91)*

Step-by-step explanation:

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Genrish500 [490]

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3 years ago

Does anyone know how to answer this question I'm having a lot of trouble with it?

Helen [10]

Answer:

h = $\frac{2A}{(b+c)}$

Step-by-step explanation:

Formula for the area of a trapezoid is,

Area (A) = $\frac{1}{2}(b+c)h$

Here b and c are the bases and 'h' is the height of the trapezoid.

2A = $2[\frac{1}{2}(b+c)h]$

2A = (b + c)h

$\frac{2A}{(b+c)}=h$

Therefore, formula for the height of the trapezoid will be,

h = $\frac{2A}{(b+c)}$

5 0

3 years ago

when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$