All categories

4 years ago

Prove that 3(x+1)(x+7)-(2x+5) ^2 is never positive

Mathematics

1 answer:

Ratling [72]4 years ago

6 0

Answer:

Step-by-step explanation:

It will never be positive becasue there is a negitive sign in the equation. negitives overule positives. Therefor it will never be positive.

You might be interested in

Image attached below. Please help.

goldfiish [28.3K]

Answer:

T,F,T,F,T

Step-by-step explanation:

1. It crosses it there becuase 4(0)-15=-15 for y

2: both top and middle answers are -23, so continuous

3: it increases over that period because the exponent keeps getting bigger

4: No, its not decreasing because -12 plugged in is far less than -23 when -2 is plugged in, meaning its increasing

5: There is no number that would cause an imaginary number or make you divide by zero, meaning all real numbers are fine.

4 0

4 years ago

there are 35 competitors in a marathon. sixty percent of these finished the race in under four hours. how many competitors finis

blagie [28]

The answer is 21. Enjoy

7 0

4 years ago

Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=

jasenka [17]

Answer:

The function $\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$ is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

$\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$

The function is continuous at point x=36 if:

The function $\\ f(x)$ exists at x=36.
The limit on both sides of 36 exists.
The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

$\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}$

$\\ f(36) = \frac{36*6}{900} = \frac{6}{25}$

The limit of the $\\ f(x)$ is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

$\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$

$\\ \lim_{x \to 36} f(x) = \frac{6}{25}$

Since

$\\ f(36) = \frac{6}{25}$

And

$\\ \lim_{x \to 36} f(x) = \frac{6}{25}$

Then, the function $\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$ is continuous at x = 36.

8 0

3 years ago

How many different nine player batting orders can be chosen from a baseball team of 16?

lawyer [7]

This problem is basically $_{16}P_9$

$_nP_r = \frac{n!}{(n - r)!}$

If I plug in n = 16 and r = 9

$\frac{16!}{(16-9)!} = \frac{16!}{7!} = 4151347200$

So there are 4151347200 different nine player batting orders that can be chosen from a baseball team of 16 :)

4 0

3 years ago

A recipe called for 2/9 cup of chopped tomatoes and 4/7 cup of diced tomatoes. In total how many cups of tomatoes did the recipe

kolbaska11 [484]

50/63

You add them

.....
........

4 0

3 years ago

Read 2 more answers