Hey there
9a+3+2a+10
You have to collect like terms
To simplify you have to add 9a and 2a. Then 3 and 10
9a+2a= 11a
10+3= 13
The answer is 11a+13
hope this helps <span />
Answer:
-7, -8 , -9 and -10 are such four integers.
Step-by-step explanation:
Let the first integer = k
So, the next three consecutive integers are ( k+1), ((k + 1) + 1) and (((k + 1) + 1) +1)
or, k , (k +1), (k +2) and (k +3) are four consecutive integers.
Now, their sum is -34.
⇒k + (k +1) + (k +2) + (k +3) = -34
or, 4k + 6 = -34
or, 4k = - 34 - 6 = -40
⇒ k = -40/ 4 = -10
Hence, the first integer k = -10
The next integer = k + 1 = -10 + 1 = -9
Similarly next two integers are -8 and - 7.
So -7, -8 , -9 and -10 are such four integers.
Look at this video: https://www.khanacademy.org/math/cc-fifth-grade-math/cc-5th-fractions-topic/cc-5th-multiplying-fraction-whole-number-product
Answer:
picture from Goldbach's conjecture.
Step-by-step explanation:
Goldbach's conjecture is one of the oldest and best-known unsolved problems in number theory and all of mathematics. It states:
Every even integer greater than 2 is the sum of two primes.
The conjecture has been shown to hold for all integers less than 4 × 10^18, but remains unproven despite considerable effort.
So on the red and blue axes you see primes. The list of black numbers are even numbers.
Sin 30° equals 0.5 and as a fraction that would be 5/10 and 5/10 simplified is 1/2
