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vodka [1.7K]
3 years ago
13

Helpp pls (39points) Can you answer this Q???

Mathematics
2 answers:
scoundrel [369]3 years ago
8 0

Answer:

Your question but don't know how to solve it like a dog

Keith_Richards [23]3 years ago
8 0
I think the right answer is the circle b
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Y'all is so nice too help me I really appreciate it help me thanks<br> plz i need help
butalik [34]
You can multiply 2/3 by 2/2 to get 4/6. This means that x=4!!!

Hope this helps :)
8 0
3 years ago
In April, 287 people visited an amusement park. In May, 379 people visited the same amusement park. In June, twice as many peopl
Mariulka [41]

Answer:

1332 i think

Step-by-step explanation:

287+379=666

666*2=1332

3 0
3 years ago
The perimeter of a rectangle must be no greater than 62 meters. The width must be 12
GREYUIT [131]

Answer:

xinloitoikogiaiduoc

Step-by-step explanti

6 0
2 years ago
Find the value of z.
omeli [17]

Applying the angle of intersecting chords theorem, the value of z is: D. 100.

<h3>What is the Angle of Intersecting Chords Theorem?</h3>

According to the angle of intersecting chords theorem, in a circle like the one shown in the image above, where two chords intersect to form vertical angles, the theorem states that the angle formed equals half of the sum of the measures of the arcs intercepted by the angles.

Applying the angle of intersecting chords theorem, let's find x first:

73 = 1/2(96 + x)

Multiply both sides by 2

2 × (73) = 1/2(96 + x) × 2

146 = 96 + x

Subtract both sides by 96

146 - 96 = 96 + x - 96

50 = x

x = 50°

Therefore:

x + z + 96 + 114 = 360° [full circle measure]

Plug in the value of x

50 + z + 96 + 114 = 360

z + 260 = 360

Subtract both sides by 260

z + 260 - 260 = 360 - 260

z = 100°

The answer is: D. 100°.

Learn more about the angle of intersecting chords theorem on:

brainly.com/question/23732231

#SPJ1

8 0
1 year ago
Find all the zeroes of the equation(with simple steps).
uysha [10]

<u>Answer-</u>

<em>The zeros are, 5,\ -5,\ 4i,\ -4i</em>

<u>Solution-</u>

\Rightarrow -3x^4+27x^2+1200=0

\Rightarrow -3(x^2)^2+27(x^2)+1200=0

Here,

a = -3, b = 27, c = 1200

So,

x^2=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

=\dfrac{-27\pm \sqrt{-27^2-4\cdot (-3)\cdot 1200}}{2\cdot (-3)}

=\dfrac{-27\pm \sqrt{729+14400}}{-6}

=\dfrac{-27\pm 123}{-6}

=\dfrac{-27+123}{-6},\ \dfrac{-27- 123}{-6}

=\dfrac{96}{-6},\ \dfrac{-150}{-6}

=-16,\ 25

So,

\Rightarrow x^2=25,\ -16

\Rightarrow x=\sqrt{25},\ \sqrt{-16}

\Rightarrow x=5,\ -5,\ 4i,\ -4i

8 0
3 years ago
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