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trapecia [35]
3 years ago
5

Find the slope and the Y-intercept of the graph of y-6=3/8x

Mathematics
2 answers:
balandron [24]3 years ago
8 0

Answer:

Slope =3/8

y-intercept is:(0,6)

Step-by-step explanation:

Mice21 [21]3 years ago
3 0

Answer:

first, we should make sure the form is y = mx + b.

y = 3/8x + 6

therefore, the slope is 3/8, and the y-intercept is 6.

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Zachary can't believe how bad London's traffic is today. In the past 10 minutes, his cab has barely moved 500 meters! He wonders
mezya [45]

Answer:

6 min

Step-by-step explanation:

5 kilometers = 5,000 meters

500/5,000 = 1/10 meaning it would take him 1/10 of an hour or 6 minutes to cover this distance.

4 0
2 years ago
2. f(8) if f(x) = x + 11
zysi [14]

f(8)=8+11=19

5 0
2 years ago
He bought four violas for 40$ each. Later he bought one whistle for 100$. After that, he returned one viola. Write the total cha
Goshia [24]
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6 0
3 years ago
Show that if X is a geometric random variable with parameter p, then
Lubov Fominskaja [6]

Answer:

\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

X\sim Geo (1-p)

In order to find the expected value E(1/X) we need to find this sum:

E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}

Lets consider the following series:

\sum_{k=1}^{\infty} b^{k-1}

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}   (a)

On the last step we assume that 0\leq r\leq b and \sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}, then the integral on the left part of equation (a) would be 1. And we have:

\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)

And for the next step we have:

\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}

And with this we have the requiered proof.

And since b=1-p we have that:

\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}

4 0
3 years ago
Melissa asked 10 students how many courses they have taken so far at her college. Here is the list of answers.
almond37 [142]

Answer:

Step-by-step explanation:

The question has asked who has taken fewer than 15 courses

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4/10  (10 is total number of options/students)

To find the percentage you...

6 0
2 years ago
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