How is the area of a triangle related to the surface area of a square pyramid
1 answer:
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See the picture to better understand the problem
we know that
in the triangle ABC
∠A+∠B+∠C=180°
∠C=180-(86+69)-----> ∠C=25°
Applying the law of sines
b/sin B=c/sin C------> b=c*sin B/sin C-----> b=82*sin 69/sin 25
b=181.14 ft
the answer is
181.14 ft
we know that
in the triangle ABC
∠A+∠B+∠C=180°
∠C=180-(86+69)-----> ∠C=25°
Applying the law of sines
b/sin B=c/sin C------> b=c*sin B/sin C-----> b=82*sin 69/sin 25
b=181.14 ft
the answer is
181.14 ft