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julia-pushkina [17]
3 years ago
8

How is the area of a triangle related to the surface area of a square pyramid

Mathematics
1 answer:
Grace [21]3 years ago
3 0
The area of a triangle is the same as the area of each triangular face 
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Lady_Fox [76]
The answer is A. 35° Celcius
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PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
ozzi

Answer:

72

Step-by-step explanation:

Just multiply all them

7 0
2 years ago
The two square pyramids are similar. The side length of the smaller pyramid is 3/4 the side length of the larger pyramid.
Triss [41]

Answer:9/16

Step-by-step explanation:

Since we know it's 3/4 use

r=(3/4)²  .... (\frac{3}{4} x\frac{3}{4} ) =\frac{9}{16}

3 0
3 years ago
In the adjoining figure, XY = XZ . YQ and ZP are the bisectors of <img src="https://tex.z-dn.net/?f=%20%5Cangle" id="TexFormula1
svetlana [45]

Answer:

See Below.

Step-by-step explanation:

Statements:                                              Reasons:

1)\, XY=XZ                                              Given

2) \text{ $ m\angle Y= m\angle Z$}                                        Isosceles Triangle Theorem

\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}                  Angle Addition

\displaystyle 4)\text{ $YQ$ bisects $\angle XYZ$}                               Given

5) \text{ $m\angle XYQ=m\angle QYZ$}                           Definition of Bisector

\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}                               Substitution

7)\text{ $m\angle Z=m\angle XZP+m\angle PZY$}              Angle Addition

8)\text{ $ZP$ bisects $\angle XZY$}                              Given

\displaystyle 9) \text{ $m\angle XZP=m\angle PZY$ }                          Definition of Bisector

\displaystyle 10) \text{ $ m\angle Z = 2m\angle PZY $}                            Substitution

11)\text{ } 2m\angle QYZ=2m\angle PZY                    Substitution

12)\text{ }m\angle QYZ=m\angle PZY                        Division Property of Equality

13)\text{ } YZ=YZ                                         Reflexive Property

14)\text{ } \Delta YZP\cong\Delta ZYQ                             Angle-Side-Angle Congruence*

15)\text{ } YQ=ZP                                         CPCTC

*For clarification:

∠Y = ∠Z

YZ = YZ (or ZY)

∠PZY = ∠QYZ

So, Angle-Side-Angle Congruence:

ΔYZP is congruent to ΔZYQ

5 0
3 years ago
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Question 6 (Essay Worth 2 points)<br> Find all polar coordinates of point P = (2, 14°).
andrey2020 [161]

Answer:

(2,14°+360n) and (-2,14°+(2n+1)180°)

Step-by-step explanation:

You start out with (2, 14°)

The polar coordinate can be written as (r, 0) = (r, 0+2nπ) or

(r,0)=(-r,0+2(n=1)π), where n is any integer.

The polar coordinates point : p=(r,0) = (2,14°)

For the positive value of r,  the polar coordinate can be written as

p=(2,14°) = (2,14°+360n°), where n is any integer.

For the negative value of r ,  the polar coordinate can be written as

p=(2,14°) = (-2,14°+(2n+1)180°), where n is any integer.

All the polar coordinates of point P are(2,14°+360n) and (-2,14°+(2n+1)180°).

4 0
3 years ago
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