3 years ago

Decimal equivalent to. 78/11

Mathematics

1 answer:

Ganezh [65]3 years ago

3 0

Just divide 78 with 11, 7.090909090909091.

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Find the area of a regular hexagon if given a side length of 1.9 to the square root of 3.

dalvyx [7]

Answer:

28.137 sq. units.

Step-by-step explanation:

Area of a regular hexagon is

$A=\dfrac{3\sqrt{3}}{2}a^2$

where, a is the side length.

It is given that the side length of the regular hexagon is $1.9\sqrt{3}$ .

Substitute $a=1.9\sqrt{3}$ in the above formula.

$A=\dfrac{3\sqrt{3}}{2}(1.9\sqrt{3})^2$

$A=(1.5\sqrt{3})(10.83)$

$A=16.245\sqrt{3}$

$A=28.137$

Therefore, the area of regular hexagon is 28.137 sq. units.

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3 years ago

A standard deck has 52 cards consisting of 26 black and 26 red cards. Three cards are dealt from a shuffled deck without replace

Allisa [31]

They aren't independent since the probability uses all the cards in the deck

So at the first deal we have the chance of 26/52 of getting a red card, at the second deal we have the chance of a 25/51 of getting another red card, so they aren't independent

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2 years ago

by 14 1 4 each week for a number of weeks, w . He writes the expression 20(14) 20 ( 1 4 ) w to find the amount of radioactive su

erastovalidia [21]

Answer:

1/2 ^w : decay factor after w weeks

hope this helps

Step-by-step explanation:

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3 years ago

Please help! I will mark you brainliest if you get the answer correctly , look at the picture.

SVETLANKA909090 [29]

Answer:

12 weeks

Step-by-step explanation:

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3 years ago

Read 2 more answers

How many cubes with side lengths of 1/3 does it take to fill the prism?

Ugo [173]

Answer:

180 cubes

Step-by-step explanation:

little cubes:

$v=(\frac{1}{3} )^{3} =\frac{1}{27}$

The prism:

$v=(\frac{5}{3})(\frac{4}{3} )(2)=\frac{40}{9} =\frac{20}{3}$

the number of cubes that fill the prism:

$cubes=\frac{\frac{20}{3} }{\frac{1}{27} } =\frac{(20)(27)}{(3)(1)}= \frac{540}{3} =180$

Hope this helps

8 0

1 year ago