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velikii [3]
3 years ago
14

Which number line represents the solutions to |x – 2| = 6? A number line from negative 10 to 10 in increments of 1. Two points,

one at negative 8 and one at 4. A number line from negative 10 to 10 in increments of 1. Two points, one at 4 and one at 8. A number line from negative 10 to 10 in increments of 1. Two points, one at negative 2 and one at 6. A number line from negative 10 to 10 in increments of 1. Two points, one at negative 4 and one at 8.
Mathematics
3 answers:
nekit [7.7K]3 years ago
5 0

Answer:

x = 8 or x = -4, i.e., the last number line

Step-by-step explanation:

|x – 2| = 6 translates to

x-2 = 6 or x-2 = -6 if you eliminate the absolute operation. So there are two solutions that you can solve independently:

x-2 = 6 => x = 8

x-2 = -6 => x = -4

iogann1982 [59]3 years ago
3 0

Answer:

C

Step-by-step explanation:

For people on ed2020

XxMandy_WolfxX2 years ago
0 0

but it's Don edgu 2021

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jek_recluse [69]

Answer:

1, 2, 3

Step-by-step explanation:

If the y's (right numbers have more than one number its not a function) hope this helps! :)

4 0
2 years ago
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Given P(E)= 0.24 and P(FnE)= 0.17, find P(F| E). Round the answer to the nearest hundredth. A. 029 B. 0.40 C. 0.71 D. 1.41
romanna [79]

Given P(E) = 0.24 and P(F ∩ E) = 0.17

It says to find conditional probability of F given E has occurred.

We know the formula of conditional probability is given by :-

P(F ║ E) = \frac{P(E\;and\; F)}{P(E)}

P(F ║ E) = \frac{0.17}{0.24} = 0.708333

P(F ║ E) = 0.71

Hence, option C i.e. 0.71 is the final answer.

7 0
3 years ago
A figure has vertices at L(3,3), M(2,4), and N(−1,0). After a transformation, the image of the figure has vertices at L′(2,−5),
alexandr402 [8]

The transformation was a reflection over the line x = -0.5

And the image and preimage can be seen in the graph below.

<h3>How to identify the preimage and image?</h3>

First, the original vertices are:

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M(2, 4)

N(-1, 0)

3 vertices means that our figure is a triangle.

Now, the transformed vertices are:

L'(2, -5)

M'(3, -4)

N'(-1, 1)

And the graph of both sets can be seen below.

Now we can try to identify the transformation.

Now, notice that all the points (L, M, N, L', N', M') are equidistant to the horizontal line x = -0.5

This is a clear implication that the transformation was a reflection over the line x = -0.5

If you want to learn more about transformations:

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3 0
1 year ago
Compare the functions below:
rjkz [21]
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6 0
3 years ago
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If the equation 3x-5y=-3, what is the value of y when x is 1
pantera1 [17]
The answer is: 6/5

Here is why:
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3 - 5y = -3
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6 0
3 years ago
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