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shtirl [24]
3 years ago
8

What is the measure of the third angle in the similar triangles below?

Mathematics
2 answers:
tiny-mole [99]3 years ago
4 0

Answer:

65

Step-by-step explanation:

A triangle has 180 degrees worth of interior degree.

So 180-(35+80) gives the remaining amount of degree (65)

pashok25 [27]3 years ago
3 0

Answer:

65°

Step-by-step explanation:

All triangles equal 180 degrees. So just subtract the other values.

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Llana [10]
The mean of your question would be -2.5
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3 years ago
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What is the slope of a line perpendicular to the line whose equation is
GenaCL600 [577]

Answer:

The slope or incline is -5

Step-by-step explanation:

rewrite to get the form

y = ...

x - 5y = -10

- 5y = -10 -x

divide left and right if the = sign by -5 gives:

(-5/-5)y = (-1/-5)x + (-10/-5)

y = 1/5x +2

So the incline is 1/5

a perpendicular line has an incline of -1 *5/1 = -5

The slope or incline is -5

4 0
3 years ago
During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

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