Question

What is the diameter of the circle whose center is at (6, 0) and that passes through the point (2, -3)?

Answer 1

Answer:

10

Step-by-step explanation:

$\left(x-h\right)^{2}+\left(y-k\right)^{2}=r^2$

$\left(x-6\right)^{2}+\left(y-0\right)^{2}=r^2$

We used (2,-3)

$\left(2-6\right)^{2}+\left(-3-0\right)^{2}=25$

$r^2=25$ , so $r = 5$

But this one is asking for the diameter, and to find it. It's simply 2r.

2*5 = 10