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(1/6) ÷ 2 = 1/12
1 ÷ 1/6 = 6
(1/10) ÷ 4 = 1/40
(1/5) ÷ 3 = 1/15
3 ÷ (1/2) = 6
2 ÷ (6/13) = 26/6 = 4 2/6 = 4 1/3
1 ÷ (3/19) = 19/3 = 6 1/3
(1/2) ÷ (1/2) = 1
(1/2) ÷ (7/9) = 9/14
(8/9) ÷ (2/3) = 24/18 = 1 6/18 = 1 1/3
Hope This Helps :)
Answer:
View solution attached below.
Hope this helps. Thanks
The positive integers are: +2, +11, +8, 28, and 13
the negative integers are: -7, -9, -11, and -3
the 0 should go in the circle between the two charts
Step-by-step explanation:
66. Δy = -3.4 Δx
Δy/Δx = -3.4
The slope of the line is -3.4. Slope-intercept equation of the line is:
y = -3.4x + b
Plug in the given point to find b:
2 = -3.4(4) + b
b = 15.6
Therefore, the equation is y = -3.4x + 15.6.
Use the equation to find the y coordinates.
![\left[\begin{array}{cc}x&y\\-4&29.2\\4&2\\6&-4.8\\18&-45.6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5C%5C-4%2629.2%5C%5C4%262%5C%5C6%26-4.8%5C%5C18%26-45.6%5Cend%7Barray%7D%5Cright%5D)
68. Repeat the same steps as 66.
Δy = -1.7 Δx
Δy/Δx = -1.7
The slope of the line is -1.7. Slope-intercept equation of the line is:
y = -1.7x + b
Plug in the given point to find b:
3 = -1.7(-7) + b
b = -8.9
Therefore, the equation is y = -1.7x − 8.9.
Use the equation to find the x or y coordinates.
![\left[\begin{array}{cc}x&y\\-19&23.4\\-7&3\\-2.412&-4.8\\3.2&-14.34\\9.1&-24.37\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5C%5C-19%2623.4%5C%5C-7%263%5C%5C-2.412%26-4.8%5C%5C3.2%26-14.34%5C%5C9.1%26-24.37%5Cend%7Barray%7D%5Cright%5D)