PLEASE HELP WILL GIVE BRAINLIEST IM TAKING TEST RN

Mathematics

1 answer:

Scrat [10]3 years ago

7 0

Answer:

I'm not 100% sure however I believe it would be x + 7x

Step-by-step explanation:

You start with what u have and then every week u get $7 each week. So I think this would be the best option however if it isnt right then I'm very sorry.

Hope this helps!

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The lifetime of a certain type of battery is normally distributed with mean value 11 hours and standard deviation 1 hour. There

victus00 [196]

Answer: The required lifetime value is 11.27.

Step-by-step explanation:

Since we have given that

Mean value = 11 hours

Standard deviation = 1 hour

The total lifetime of all batteries in a package exceeds that value for only 5% of all packages.

So, α = 0.95, z= 1.645

n = 9

So, the lifetime value would be

$x=\mu+z\times \dfrac{\sigma}{\sqrt{n}}\\\\x=11+1.645\times \dfrac{1}{\sqrt{36}}\\\\x=11+1.645\times \dfrac{1}{6}\\\\x=11.27$

Hence, the required lifetime value is 11.27.

5 0

4 years ago

The difference between the squares of two numbers is 20. three times the square of the first number increased by the square of t

Mashcka [7]

We need a system of equations to solve this. "Difference" is to subtract, and we are taking this difference of the 2 squared unknowns to be 20. That equation is $x^{2} -y^2=20$ . Our "first number is x^2, so 3 times that is 3x^2. "Increased by" is adding to that first number. What we are adding is the second number. The second equation is $3x^2+y^2=124$ . Let's solve the first equation for x^2: $x^2=y^2+20$ and sub that value for x^2 into the second equation. $3(y^2+20)+y^2=124$ and $3y^2+60+y^2=124$ . Subtract 60 from both sides and combine the y^2 terms to get $4y^2=64$ . Divide both sides by 4 to get y^2 = 16 and y = 4. Let's go back now and solve for x. We will use the fact that y^2 = 16 to solve for x^2 and then take the square root of it. $x^2-16=20$ , x^2 = 4, so x = 2. Your solutions are x = 2 and y = 4. There you go!

8 0

3 years ago

What's the answer to this?

beks73 [17]

Answer:

Q' = (-4, -2)

R' = (4, -2)

S' = (4, 2)

T' = (-4, 2)

Step-by-step explanation:

First, we can create a matrix to scale this rectangle by putting all the x coordinates in the top row and all the y coordinates in the bottom row and multiply it by 4.

Our initial matrix to multiply:

$4\left[\begin{array}{cccc}-1&1&1&-1\\-2&-2&-1&-1\end{array}\right]$