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Nitella [24]
3 years ago
10

Does it matter what order you add integers?

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0

Answer:

it depends with what you are doing or using them for

It depends with what you are doing with them

Alinara [238K]3 years ago
4 0

Answer:

Yes!

Step-by-step explanation:

If not people won't understand the concept of the problem you are working on. Hope this helps please reward me brainlist!!!

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Please help me on all 4 or on just numbers 6,7,8
belka [17]

Answer:

5. Not sure

6. Its linear since the first difference is constant.

7. Linear since its a line.

8. Slope/Rate of Change/M = Rise over Run = rise/run.

From the left point to the right, the rise is 3 and run is 10.

M =  3/10.

Hope this helped

Step-by-step explanation:

7 0
3 years ago
Really need this todayyyyyy
Bond [772]

Answer:

Q3: x1=2+i, x2=2-i Q4: x1=-3/2+i, x2=-3/2-i

Step-by-step explanation:

x^{2} - 4x + 5 =0

( 4± \sqrt{16 - 4*1*5} ) / 2 = (

x1= 2+i

x2= 2-i

2x^{2} +6x + 5 =0

( -6 ± \sqrt{36 - 4*2*5} ) / 4 = (-6 ± \sqrt{-4} )/4= (-3 ± i)/2

x1 = -3/2 +i

x2 = -3/2 -i

7 0
3 years ago
Read 2 more answers
A 2005 survey found that 7% of teenagers (ages 13 to 17) suffer from an extreme fear of spiders (arachnophobia). At a summer cam
bagirrra123 [75]

Answer:

Probability that at least one of them suffers from arachnophobia is 0.5160.

Step-by-step explanation:

We are given that a 2005 survey found that 7% of teenagers (ages 13 to 17) suffer from an extreme fear of spiders (arachnophobia).

Also, At a summer camp there are 10 teenagers sleeping in each tent.

Firstly, the binomial probability is given by;

P(X=r) =\binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,....

where, n = number of trials(teenagers) taken = 10

           r = number of successes = at least one

          p = probability of success and success in our question is % of

                the teenagers suffering from arachnophobia, i.e. 7%.

Let X = Number of teenagers suffering from arachnophobia

So, X ~ Binom(n= 10,p=0.07)

So, probability that at least one of them suffers from arachnophobia

= P(X >= 1) = 1 - probability that none of them suffers from arachnophobia

= 1 - P(X = 0) = 1 - \binom{10}{0}0.07^{0}(1-0.07)^{10-0}

                       = 1 - (1 * 1 * 0.93^{10} ) = 1 - 0.484 = 0.5160 .

Therefore, Probability that at least one of them suffers from arachnophobia is 0.5160 .

3 0
3 years ago
A train traveling at a constant speed takes a passenger from Elm to Millwood, stopping at Centre along the way. It takes 2004-01
ZanzabumX [31]
The complete problem is as following:
A train traveling at a constant speed takes a passenger from Elm to Millwood, stopping at Centre along the way. It takes 5 times as long to go from Centre to Millwood as it does to go from Elm to Centre. The entire trip is 48 miles. How far is the ride from Centre to Millwood? Name a geometric postulate or theorem used to find the solution. 
A) 8 miles ; segment addition postulate 
B) 8 miles; segment bisector theorem 
C) 40 miles; segment addition postulate 
D) 40 miles; segment bisector theorem
=======================================================
Solution ;
Let the time taken from Elm to Centre = x  ⇒⇒⇒ segment (1)

∴ the time taken from Centre to Millwood = 5x  ⇒⇒⇒ segment (2)

∴ Total time of all the trip = x + 5x = 6x
The entire trip is 48 miles and the train traveling with constant speed
∴ speed = distance over the time = \frac{48}{6x} =  \frac{8}{x}
So, the distance from Centre to Millwood = speed * time = \frac{8}{x} * 5x = \framebox{40 \ miles}
As seen in the answer, we have added the segment (1) to segment (2)
So, The geometric postulate used to find the solution is segment addition postulate

So, the correct option is C) 40 miles; segment addition postulate

=======================================================
Another solution :
From Elm to Centre = x ⇒⇒⇒ segment (1)
From Centre to Millwood = 5x ⇒⇒⇒ segment (2)
∵ The train traveling with constant speed 
∴ Distance is proportional with the time
By using the ratio and proportional as following 

Segment (1) : segment (2) : Total \\ \ \ 
. \ \ \ \ \ \ \  x \ \ \ \  \ \  :  \ \ \ \ \ 5x \ \ \ \ \ \ \ : \ \ 6x \\
. \ \ \ \ \ \ \  ? \ \ \ \  \ \  :  \ \ \ \ \ \ \ ? \ \ \ \ \ \ \ \ : \ \ \ 48

∴ segment (2) = \frac{48 * 5x}{6x} = \framebox {40 miles}


we have used the postulate of segment addition to add x and 5x.

So, the correct option is C) 40 miles; segment addition postulate
4 0
4 years ago
Convert 549/ 999 to a decimal.
Setler [38]
You divide 549/999, which makes 0.54954955
0 0
3 years ago
Read 2 more answers
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