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3 years ago

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The life in hours of a 75-watt light bulb is known to be normally distributed with σ = 25 hours. Suppose that you wanted the tot

al width of the two-sided confidence interval on the mean life to be six hours at 95% confidence. What sample size should be used?

1 answer:

Temka [501]3 years ago

4 0

Answer:

Step-by-step explanation:

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Find area and perimeter show your work

yan [13]

Answer:

A= 16

P=16

Step-by-step explanation:

A=h^bxb/ 2

P= side+base+side

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1 year ago

The measure of one of the angles formed by two parallel lines and a transversal is 45°. Is it possible for the measure of any of

liubo4ka [24]

Answer: No

Step-by-step explanation:

Three of the other angles are 45°. The other four are 180° - 45°, which is not 55°. At the intersection of two lines, opposite angles are equal and adjacent angles are complementary, so two adjacent angles add to 180°. Adding a parallel line gives four more angles identical to the first four.

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3 years ago

Simplify.<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B8%5Csqrt%7B6mn%7D%20%2B%206%5Csqrt%7B8mn%7D%20%7D%7B2%5Csqrt%7B2mn%7D%

nata0808 [166]

It’s the first answer
I used Math-way :)

3 0

2 years ago

Question 2 of 18

Ilya [14]

Answer:

B

Step-by-step explanation:

g(x)=(4-4)²

g(x) =0

and f(x)=x²

f(x)=0²

4 0

1 year ago

Consider circle T with radius 24 in. And 0=startfraction 5 pi over 6 endfraction radians. Circle T is shown. Line segments S T a

satela [25.4K]

Answer:

$20\pi $ inches or \approx 62.83$ inches$

Step-by-step explanation:

$\text{Central Angle of Arc SV}=\dfrac{5\pi}{6}$ rad$\\\text{Radius of Circle T}=24 in.\\\\\text{Length of an arc} = \dfrac{\theta}{2\pi} \times 2\pi r$

Therefore:

$\text{Length of minor arc SV} = \dfrac{\frac{5\pi}{6}}{2\pi} \times 2\pi \times 24\\=20\pi $ inches\\\approx 62.83$ inches$

The length of minor arc SV is 62.83 inches.

7 0

2 years ago