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3 years ago

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The life in hours of a 75-watt light bulb is known to be normally distributed with σ = 25 hours. Suppose that you wanted the tot

al width of the two-sided confidence interval on the mean life to be six hours at 95% confidence. What sample size should be used?

1 answer:

Temka [501]3 years ago

4 0

Answer:

Step-by-step explanation:

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Will took two tests and made an 83% and a 93%. What will he need to make on the next test to have a mean score of 90%

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Step-by-step explanation:

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2 years ago

mean of 164,175,178,166,167,145,176,150,174,162,180,156,173,158,182,184,160,172,186,168,195,169,171,187,170

Karo-lina-s [1.5K]

Answer:

170.72

Step-by-step explanation:

to find the mean, we must add al the numbers and divide it by n

that is,

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sum- 4628 divided by 25

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1 year ago

Simplify the expression <br> -7(3e-2f+4)+6e-2

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3 years ago

An initial of the $100 is now valuated at $150. The annual interest rate is 5%, compounded continuously. The equation 100e^0.05=

tangare [24]

Answer:

8 years approximately

The problem (I'm assuming is):

Solve $100e^{0.05t}=150$ .

I put a t in the problem where I suspected it in went.

Step-by-step explanation:

$100e^{0.05t}=150$

Divide both sides by 100:

$e^{0.05t}=\frac{150}{100}$

$e^{0.05t}=1.5$

Rewrite in logarithm form.

$\ln(1.5)=0.05t$

Divide both sides by 0.05:

$\frac{\ln(1.5)}{0.05}=t$

Put left hand side into calculator:

$8.109 \approx t$

$t \approx 8.109$

So about 8 years if I wrote down the equation correctly.

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2 years ago

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