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USPshnik [31]
3 years ago
10

Classify the relations according to whether or not they are functions.

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0
First of all, let's explain the term relation. Many everyday phenomena involve two quantities that can be related to each other by some rule of correspondence. In mathematics the term for such a rule of correspondence is called relation. Relations are often represented by mathematical equations and formulas.

Suppose you have a set A and a set B, so if a relation assigns to each element x in the set A exactly one element y in the set B, then the function f is in fact that relation.
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It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i
USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 55, \pi = \frac{24}{55} = 0.4364

93% confidence level

So \alpha = 0.07, z is the value of Z that has a pvalue of 1 - \frac{0.07}{2} = 0.965, so Z = 1.81.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0
3 years ago
What are the zeros of the polynomial function f(x) = x3 - 2x2 - 24x? (1 point)
vodka [1.7K]

f(x) = x³ - 2x² - 24x

x³ - 2x² - 24x = 0

x(x² - 2x - 24) = 0

x = 0

x² - 2x - 24 = 0

a = 1, b = -2, c = -24

Delta = (-2)² - 4 * 1 * (-24) = 4 + 96 = 100

x = (-(-2) - 10)/(2 * 1) = -8/2 = -4

x = (-(-2) + 10)/(2 * 1) = 12/2 = 6

Answer: 2)

5 0
3 years ago
What is the equation in point slope form of the line that passes through the point (−1, −3) and has a slope of 4?
lutik1710 [3]

I agree with the second answer. Was this correct?



8 0
3 years ago
How do i rearrange a(x-y)=b(z-x) to make x the subject?
Ket [755]

Answer:here's ur answer

Step-by-step explanation:

4 0
3 years ago
On a coordinate plane, a curved line labeled f of x with a minimum value of (1.9, negative 5.7) and a maximum value of (0, 2), c
Vikentia [17]

Answer: 4.F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞).

Hope this helps :)

5 0
3 years ago
Read 2 more answers
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