Answer:
A) car one is linear because it decreases the same amount every year.
car two decreases by the same ratio so it's exponential.
B) for car one y = -6,000x + 38,000 (y is the value after x years, -6,000 is what it changes by every year, and 38,000 is the amount of year 0)
for car two y = (44,000) (17/20)x-1 (y is the value after x years, 44,000 is the amount on year 0, and 17/20 is the ratio)
C) after 5 years car one will be 8,000
after 5 years car two will be about 16,860
Answer: 
<u>Step-by-step explanation:</u>
EQ1: x + y = 12 --> x = 12 - y
EQ2: xy = 15
Substitute x = 12-y into EQ2 to solve for y:
(12 - y)y = 15
12y - y² = 15
0 = y² - 12y + 15
↓ ↓ ↓
a=1 b= -12 c=15
Now, let's solve for x:
Lastly, find x² + y² :
Answer:
1/4 of a mile in 1/10 of an hour
you can set up a proportion
(1/4)/(1/10)=2/H
you can now simplify or cross multiply
simplifying the left side
(1/4) divided by (1/10) equals (1/4) times (10/1)
(1/4)*(10/1)=10/4=5/2
5/2=2/H
cross multiply
5H=2*2
5H=4
H=4/5 of an hour or (4/5)*60=48 minutes
another solution...
2/(1/4)=8 and 8*(1/10)=8/10=4/5 of an hour or 48 minutes again
