Answer:
x ={0; - 1 ; 2 ; 1}
Step-by-step explanation:
x¹³-2x¹²-x¹¹+2x¹⁰=0
x¹⁰(x³-2x²-x+2)=0
x¹⁰(x+1)(x-2)(x-1)=0
x¹⁰=0 ∨ x+1=0 ∨ x-2=0 ∨ x-1=0
x=0 x= - 1 x= 2 x= 1
Given:
The expression is:

To find:
The integration of the given expression.
Solution:
We need to find the integration of
.
Let us consider,

![[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ccos%202x%3D2%5Ccos%5E2x%2C1-%5Ccos%202x%3D2%5Csin%5E2x%5D)

![\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Ctan%20%5Ctheta%20%3D%5Cdfrac%7B%5Csin%20%5Ctheta%7D%7B%5Ccos%20%5Ctheta%7D%5Cright%5D)
It can be written as:
![[\because 1+\tan^2 \theta =\sec^2 \theta]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ctan%5E2%20%5Ctheta%20%3D%5Csec%5E2%20%5Ctheta%5D)


Therefore, the integration of
is
.
my number 5467832342
Step-by-step explanation:
There are 2001 items in that set.
So n(A) = 2001
We can individually count them all out, which is very slow and tedious, or we can use the formula
n-m+1
where,
m = starting value
n = ending value
In this case,
m = 0
n = 2000
So,
n-m+1 = 2000-0+1 = 2001
This formula only works if we increase the number by 1 each time (eg: 6, 7, 8, etc)