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3 years ago

What number is in between 3.75 and 4.00?

2 answers:

8 0

✡ Answer: 3.76, 3.77, 3.78, 3.79, 3.80, 3.81, 3.82, 3.82, 3.83, 3.84, 3.85, 3.86, 3.88, 3.89, 3.90, 3.90, 3.91, 3.92, 3.93, 3.94, 3.95, 3.96, 3.97, 3.98, 3.99 ✡

- - Are all the numbers between 3.75 and 4.00
- - But you can also say "3.90" for only one number if needed.

✡Hope this helps✡

natulia [17]3 years ago

5 0

3.76, 3.77, 3.78, 3.79, 3.80, 3.81, 3.82, 3.82, 3.83,

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The midpoint of GH are M(4,3) and D(5,-6). The coordinates of the endpoint are?

Phantasy [73]

Answer:

The endpoint coordinates are (3,12)

Step-by-step explanation: $\frac{5+x^{2} }{2} =4$ $\frac{-6+y^{2} }{2} = 3$

You multiply 4 by 2 which gives you 8 and write the equation $5+x^{2} =8$ then you subtract 5 from 8 to get 3 for the x coordinate.

You multiply 3 by 2 which gives 6 and writhe the equation $-6+y^{2}=6$ then you substitute the -6 for +6 and add +6 and 6 to get 12 for the y coordinate.

To check use the midpoint formula with coordinates D and your endpoint coordinates $\frac{5+3}{2}=\frac{8}{2} =4 \\$ $\frac{-6+12}{2} =\frac{6}{2} =3$ and you get the answer for the midpoint which is (4,3)

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2 years ago

PLEASE HELP!!!!! What is the value of x in the matrix equation below?

Brums [2.3K]

The given matrix equation is,

$1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]$ .

Multiplying the matrices with the scalars, the given equation becomes,

$\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$

Adding the matrices,

$\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$

Matrix equality gives,

$1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2$

Solving the equations together,

$y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10$

We can see that the equations are not consistent.

There is no solution.

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3 years ago

A motor club has estimated that a 325 mile car trip will take 6 1/2 hours. What is the club assuming to be the average speed mil

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Answer:

The average speed that the club is assuming is 50 miles per hour

Solution:

We know that Distance = Speed × Time.

Here it is given that distance is 325 miles and the time to cover 325 miles is $6_{2}^{1}$ hours which is equal to $\frac{13}{2}$ hours.

Now to find the average speed mile per hour we use the formula

$\begin{aligned} \text { Speed } &=\frac{\text { Distance }}{\text { time }} \\ &=\frac{325}{\frac{13}{2}} \\ &=\frac{325 \times 2}{13} \end{aligned}$

By cancelling 325 by 13 we get 25

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= 50 miles per hour

Thus the average speed that the club is assuming is 50 miles per hour.

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3 years ago