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erastovalidia [21]
3 years ago
15

Jeremiah received $65 for his birthday and used part of it to buy 3 video games. The games cost the same amount, and he had $14

left. Write the algebraic equation used to determine how much each game cost.
Mathematics
2 answers:
enyata [817]3 years ago
8 0
(65-14)/3=G G=amount each video game cost
Dmitry_Shevchenko [17]3 years ago
7 0
65-3x=14 is the algebraic equation
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50 POINTSSSSSSS!!!!!!!!!!!!!!!!!!!!!!!!!!!
WARRIOR [948]

Answer:

where is the 50 points mate

Step-by-step explanation:

4 0
3 years ago
Actual lengths of pregnancy terms for a particular species of mammal are nearly normally distributed about a mean pregnancy leng
HACTEHA [7]

Solution :

The data is normally distributed.

The standard deviation is 18 days

Here the data is normally distributed and 54 days is 3 days of standard deviation.

Therefore, the percentage of the births that would be \text{expected to occur} within the 54 days of the mean \text{pregnancy} length is given by :

= P( -3 < Z < 3)

= 0.9544

= 95 %

Therefore, about 95% of the births would be \text{expected to occur} within 54 days of the men \text{pregnancy} length.

8 0
2 years ago
Find e^cos(2+3i) as a complex number expressed in Cartesian form.
ozzi

Answer:

The complex number e^{\cos(2+31)} = \exp(\cos(2+3i)) has Cartesian form

\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2).

Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}.

Then,

\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}. (I)

Now, recall the definition of the complex exponential:

e^{z}=e^{x+iy} = e^x(\cos y +i\sin y).

So,

e^{2i-3} = e^{-3}(\cos 2+i\sin 2)

e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

Thus,

e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)

Now we group conveniently in the above expression:

e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2.

Now, substituting this equality in (I) we get

\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2.

Thus,

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

5 0
2 years ago
(6x - 5y = 34 Lin is solving this system of equations: 3x +2y = 8 She starts by rearranging the second equation to isolate the y
Norma-Jean [14]

Answer:

It is a little hard to see where your steps are for the equation, but x = 4, and I will explain:

Step-by-step explanation:

We know y = -1.5x +4, so we plug that into the equation

6x - 5(-1.5 + 4) = 34

6x +7.5x - 20 = 34    Here we distributed the -5 into the parenthesis.

13.5x -20 = 34

13.5 = 54

x = 4

Hope this helps!

4 0
3 years ago
Two lines and a point are guaranteed to be coplanar If..
Roman55 [17]
Two lines and a point are guaranteed to be coplanar if the two lines share only a single point.

Hope this helped :)
8 0
3 years ago
Read 2 more answers
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