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3 years ago

Which equation represents the line that passes through the points (6,3) and is parallel to y=1/2x+8

Mathematics

1 answer:

Dima020 [189]3 years ago

5 0

Answer:

y = $\frac{1}{2}$ x

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{1}{2}$ x + 8 ← is in slope- intercept form

with slope m = $\frac{1}{2}$ , thus

y = $\frac{1}{2}$ x + c ← is the partial equation

To find c substitute (6, 3) into the partial equation

3 = 3 + c ⇒ c = 3 - 3 = 0

y = $\frac{1}{2}$ x ← equation of parallel line

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PLEASE HELP

Oksana_A [137]

Answer:

A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).

Hope it helped.

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4 0

2 years ago

Find the product of 4/5 and 5/12 put in simplest form

kotegsom [21]

Hello!

The answer is 20/60 simplest form is 1/3

To get 20/60 you must multiply the Numerator by Numerator (4*5) and Denominator by Denominator (5*12). Your answer will be 20/60.

To get 1/3 you must simplify a number that can go into 20 and 60 (which is 10). Divide 20/10 and 60/10 and get 2/6. Simplify 2/6 by 2 and get 1/3.

3 0

3 years ago

Choose whether it's always, sometimes, never

Keith_Richards [23]

Answer: An integer added to an integer is an integer, this statement is always true. A polynomial subtracted from a polynomial is a polynomial, this statement is always true. A polynomial divided by a polynomial is a polynomial, this statement is sometimes true. A polynomial multiplied by a polynomial is a polynomial, this statement is always true.

Explanation:

The closure property of integer states that the addition, subtraction and multiplication is integers is always an integer.

If $a\in Z\text{ and }b\in Z$ , then a+b\in Z.

Therefore, an integer added to an integer is an integer, this statement is always true.

A polynomial is in the form of,

$p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0$

Where $a_n,a_{n-1},...,a_1,a_0$ are constant coefficient.

When we subtract the two polynomial then the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

If a polynomial divided by a polynomial then it may or may not be a polynomial.

If the degree of numerator polynomial is higher than the degree of denominator polynomial then it may be a polynomial.

For example:

$f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2$

Then $\frac{f(x)}{g(x)}=x^2+5$ , which a polynomial.

If the degree of numerator polynomial is less than the degree of denominator polynomial then it is a rational function.

For example:

$f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2$

Then $\frac{g(x)}{f(x)}=\frac{1}{x^2+5}$ , which a not a polynomial.

Therefore, a polynomial divided by a polynomial is a polynomial, this statement is sometimes true.

As we know a polynomial is in the form of,

$p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0$

Where $a_n,a_{n-1},...,a_1,a_0$ are constant coefficient.

When we multiply the two polynomial, the degree of the resultand function is addition of degree of both polyminals and the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3 0

3 years ago

Read 2 more answers

X^2-x+12 solve using the quadratic formula

devlian [24]

The quadratic formula is $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$ .

From the problem, a is 1, b is -1, and c is 12. Plugging in these values gives:

$x=\frac{-(-1(-1)\pm\sqrt{(-1)^2-4(1)(12)} }{2(1)}$

Because there is a square root of a negative number, there is no solution.

4 0

4 years ago

5 The cost of an adult's ticket into a theme park is $a.

natta225 [31]

Answer:

<u>Total Cost (in dollars) = a + c</u>

Step-by-step explanation:

<u>Algebra</u>

When mathematics quantities are generalized into letters or variables, then we are dealing with algebra.

We are said the cost of an adult's ticket into a theme park is $a and a child's ticket costs $c. Since both quantities are unknown, we must treat them as variables and use the same logic procedure to solve the problem as if they were numbers.

The total cost for an adult and a child is the sum of both individual costs, thus

Total Cost (in dollars) = a + c

4 0

3 years ago