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3 years ago

About 4/10 of the population has blood type O+. What percent of the population has blood type O+?

2 answers:

4 0

If 4/10 of the population have blood type O+, that means 40% of the population have that blood type. To change a fraction to percent, the easiest way is to make the denominator 100. To do this, multiply the whole fraction by 1 (1/1, 2/2, etc). In this case, multiply by 10/10. 4/10 * 10/10 is equal to 40/100. Then, if you have a denominator of 100, the numerator is the percent. Therefore, 40/100 is 40%.

IrinaVladis [17]3 years ago

3 0

Answer:

40%

Step-by-step explanation:

4/10 = 40/100 common denominators

or %40

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Please help me with this question

Zinaida [17]

Tree C is the proper tree. The first game has the possibility of a win, a loss, or a tie which the first row represents. The second game could also win, lose or tie, meaning each result would have each possibilty for that game.

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3 years ago

Whoever answers correctly can have brainliest<br> but answer asap

Valentin [98]

Answer:

3 1/3

Step-by-step explanation:

2 1/2 = 5/2

1 1/3 = 4/3

5/2×4/3

5×4/2×3=

20/6=

10/3 = 3 1/3

3 0

1 year ago

Read 2 more answers

Jay factored the 4 term polynomial : x^3 - 9x +2x^2 - 18 and decided that the complete factorization was : ( x + 2 ) (x^2-9 ). B

labwork [276]

Answer:

$x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

Step-by-step explanation:

we are given that $x^3-9x+2x^2-18$

w are sked to step by step factorise the above polynomial

$\left(x^3+2x^2\right)+\left(-9x-18\right)$

$-9\mathrm{\:from\:}-9x-18\mathrm{:\quad }-9\left(x+2\right)$

$-9x-9\cdot \:2$

$-9\left(x+2\right)$

$\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}x^3+2x^2\mathrm{:\quad }x^2\left(x+2\right)$

$-9\left(x+2\right)+x^2\left(x+2\right)$

$\left(x+2\right)\left(x^2-9\right)$

$x^2-9:\quad \left(x+3\right)\left(x-3\right)$

$x^2-9$

$\mathrm{Rewrite\:}9\mathrm{\:as\:}3^2$

$=x^2-3^2$

$\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$

$x^2-3^2=\left(x+3\right)\left(x-3\right)$

Hence

$x^3-9x+2x^2-18=\left(x+2\right)\left(x+3\right)\left(x-3\right)$

a) The jay mistake was he did not factorise $x^3-9x+2x^2-18x^2-9 furtherb) the complete answer wil be [tex]x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

8 0

3 years ago

Read 2 more answers

A pack of 4 rolls of Charmin cost $3.64. A pack of 32 rolls of Charmin cost $20.80. How much cheaper per roll is it to purchase

MissTica

Answer:

.26 cents cheaper a roll

Step-by-step explanation:

to find this you would do 3.64/4 to get the price a roll which is .91

and then you would do 20.80/32 to get the price per roll which is .65

then to get the difference you would do .91-.65 to get .26

6 0

2 years ago

Solve -28<2x-10<-10

Sedbober [7]

-28 < 2x - 10 < -10.....add 10 to all sections
-28 + 10 < 2x - 10 + 10 < -10 + 10....simplify
-18 < 2x < 0...divide all sections by 2
-18/2 < 2/2x < 0/2...simplify
-9 < x < 0 <===

5 0

2 years ago