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erik [133]
4 years ago
9

Given that f(x) = 6x2 + 72, find x.

Mathematics
2 answers:
Aneli [31]4 years ago
4 0
<h3>Answer:</h3>

Values of x are:

±2i√3

<h3>Step-by-step explanation:</h3>

We have to find x in f(x)=6x²+72

i.e. those values of x for which

6x²+72=0

Subtracting 72 from both sides, we get

6x² = -72

Dividing both sides by 6, we get

x² = -12

Taking square root on both sides, we get

x = ±2i√3

Hence, Values of x are:

±2i√3

Alexeev081 [22]4 years ago
3 0

We have been given that

f(x) = 6x^{2} +72

f(x)-72=6x^{2}

\frac{f(x)-72}{6} =x^{2}

x=\sqrt{\frac{f(x)-72}{6} }

Hence, x=\sqrt{\frac{f(x)-72}{6} }.

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