Answer:
D
Step-by-step explanation:
(f • g)(x)
= f(x) × g(x)
= (x + 4)(3x² - 7)
each term in the second factor is multiplied by each term in the first factor , that is
x(3x² - 7) + 4(3x² - 7) ← distribute both parenthesis
= 3x³ - 7x + 12x² - 28
= 3x³ + 12x² - 7x - 28 ← in standard form
A:40%
If you put 60 over 150 and x(percent of students) over 100 and cross multiply 100 and 60, you will get 6000. You then divide that by 150 which leaves you with 40 as x and 40 over 100 is 40%.
Answer:
k = - 6.6667
Step-by-step explanation:
this is quite very simple to begin. I would encourage you take other practice questions similar to help with understanding it.
let us begin.
Given that ;
dT/dt = k ( Tm - T) where Tm is the temp of the medium
dT/dt = 5 degrees Celsius per minute when T = 70
so we have that, 5 = k ( 25 - 70)
remember to convert 5 degree celsius per minute to seconds
we have that;
5*60(sec) = k ( 25 - 70)
k = 5*60 / ( 25 - 70)
k = - 6.6667
note K is negative because we consider it for cooling process (temp decreasing).
cheers i hope this helps!!!
Answer:
<em>Pool 1 leaks faster than pool 2.</em>
Step-by-step explanation:
<u>Rates of change</u>
The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.
We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.
To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:
15 minutes = 15/60 = 1/4 hours
20 minutes = 20/60 = 1/3 hours
Now compute both rates of change:
Pool 1:

Pool 2:

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.