1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Butoxors [25]
3 years ago
15

Hello I'm having trouble with my homework and I can't understand it very well. I just want to know what is P(6, 2). my subject i

s on permutations.
Mathematics
1 answer:
TEA [102]3 years ago
6 0
6!/(6 - 2)! = 30

The calculator provided computes one of the most typical concepts of permutations where arrangements of a fixed number of elements r, are taken from a given set n. Essentially this can be referred to as r-permutations of n or partial permutations, denoted as nPr, nPr, P(n,r), or P(n,r)among others. In the case of permutations without replacement, all possible ways that elements in a set can be listed in a particular order are considered, but the number of choices reduces each time an element is chosen, rather than a case such as the "combination" lock, where a value can occur multiple times, such as 3-3-3. 
You might be interested in
This is an easy question but it’s kind of stumping me, please help!!
Kryger [21]

Answer:

-3/2

Step-by-step explanation:

Remeber, to find slope we use this formula:

y - y all over x - x, or (y-y) / (x-x)

(6-9) / (5-3)

-3 / 2

= -3/2

6 0
3 years ago
Read 2 more answers
Use absolute value notation to represent the distance between x and 8 is no more than 4
ivanzaharov [21]
The distance: use absolute value
Between x and 8: x-8

The distance between x and 8: | x-8 |

“is no more than” means it can be that or be less than that, so use ≤

The distance between x and 8 is no more than 4

| x-8 | ≤ 4
3 0
3 years ago
If a 40-foot tree casts a 16-foot shadow, find the length of the shadow cast by a 24-foot tree
Mrrafil [7]

40/16 = 24/x

16*24 = 384

x = 384 / 40

x =9.6

 it cast a shadow 9.6 feet long

8 0
3 years ago
Please help me with this question
Bezzdna [24]

Answer:

1.03

Step-by-step explanation:

To find the volume of a prism, find the area of the base and multiply it by the height.

The base is an octagon. The area is found A = 2(1+\sqrt{2})a^2. Substitute a = 0.5.

A = 2(1+\sqrt{2})(0.5^2)\\A = 4.828...(0.25)\\A = 1.21

The volume is 1.21*2.5 = 3.025.

However, there are three holes drilled out half way which each have volume 0.06.

The volume is found as V = πr²h. Substitute r = 0.125 which is half the diameter of 0.25. Since they go half way, the height is h = 1.25.

V = π(0.125)²(1.25) = 0.06.

Since there are 3, they equal 3*0.06 = 0.18.

Subtract this from the volume.

1.21 - 0.18 = 1.03

4 0
3 years ago
Assume that the probability of any newborn baby being a girl is one half
asambeis [7]

Answer:

1/32

Step-by-step explanation:

P(0 girls)

= P(5 boys)

= (1 − ½)⁵

= 1/32

7 0
4 years ago
Other questions:
  • How much is 12 ft by 14 ft in square feet
    13·2 answers
  • Write an equation of the parabola in vertex form
    11·1 answer
  • Find the surface area of a square pyramid with side length 3 cm and slant height 6<br>cm.​
    14·2 answers
  • What is angle "b" ?<br> 45 degrees<br> 60 degrees<br> 50 degrees<br> 40 degrees
    8·1 answer
  • How would you write(-5,-1) (-3,-2) and(-3,2) if it is rotating 90° clockwise​
    7·1 answer
  • In a long distance race, Adele ran 5 fewer kilometers than twice the number than Bryce ran. Together they ran at least 43 km. Wh
    6·1 answer
  • Find the x-intercept of y = -x - 20
    10·1 answer
  • A cyclist rides her bike at a speed of 10 miles per hour. What is this speed in kilometers per hour? How many kilometers will th
    10·2 answers
  • Which of the following systems of linear equations has no solution?
    14·2 answers
  • Toni can carry up to 19 lb in her backpack. Her lunch weighs 1 lb, her gym clothes weigh 2 lb, and her books (b) weigh 4 lb each
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!