D. All of the above. They are all rational numbers
Construct the perpendicular bisector of one side of triangle
Construct the perpendicular bisector of another side
Where they cross is the center of the Circumscribed circle
Place compass on the center point, adjust its length to reach any corner of the triangle, and draw your Circumscribed circle!
Hello :
<span>B) b = 3a + 2
a= 2 b = 3(2)+2 =8
</span>a= 4 b = 3(4)+2 =14
a= 6 b = 3(6)+2 =20
Step-by-step explanation:
Okay, so the triangle would look something like this:
see the image attached
Since AB=AC, which is given; <ABD = <ACD, because they are the angles opposite from the congruent sides of the isosceles triangle; and <ADB=<ADC, as AD is the bisector*; ΔABD ≅ ΔACD using SAA/AAS (side-angle-angle) congruencey.
*If the bisector of an angle in a triangle meets the opposite side at its midpoint, then the triangle is isosceles, and vice versa
(I haven't done Geometry in a while so I hope that's correct :) )