Answer:
substitute x=1/2 in the equation then it will be

<u>In Bar Graphs;</u>
- Bars have equal space
- One the y-axis, we have numbers & on the x-axis, we have data which can be anything.
<u> In Histograms;</u>
- Bars are fixed
- On the y-axis, we have numbers & and on the x-axis, we have data which in continuous & will always be number.
<u>An easy way you can remember the difference is looking at the spaces of the bars. </u>
<em>A bar graph has gaps</em>
<em>A histogram has no gaps.</em>
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
Exact form: x= NEGATIVE 6/7
9514 1404 393
Answer:
$8,775
Step-by-step explanation:
The amount due is given by the formula ...
A = P(1 +rt)
where P is the principal amount, r is the annual rate, and t is the number of years.
A = $6,500(1 +0.07×5) = $6,500(1.35) = $8,775
Montrey had to pay back $8,775.