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STatiana [176]
3 years ago
9

What is the value of x in the following equation 1/5x=5^8 A)-8 B) 8 C)40 D)-40

Mathematics
1 answer:
Monica [59]3 years ago
7 0
The correct question is
What is the value of x in the following equation (1/5)^x=5^8 

Applying logarithms both members
log(1/5)^x=log(5^8) 
x*log(1/5)=8*log(5)
x=8*log(5)/log(1/5)

we know that
log (1/5)----> log (1)-log (5)----> 0-log (5)-----> -log (5)
so
x=8*log(5)/-log (5)------> x=-8

the answer is
-8

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The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me
Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

\mu = \frac{5(0.1) + 2(0.2)}{7} = 0.1286

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?

This is P(X = 2). So:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

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Answer:

First question: -0.577 cannot be a probability.

Second question: The number must be between 0 and 1, inclusive (D)

Third question: -0.577 cannot be a probability.

Step-by-step explanation:

A probability is a real number that is in the interval [0, 1]. Therefore, any number outside this range cannot be considered a probability. Under this premise:

First question: -0.577 cannot be a probability.

Second question: The number must be between 0 and 1, inclusive (D)

Third question: -0.577 cannot be a probability.

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Paul [167]

Answer:

x = 4\sqrt{5}

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 1² = 9²

x² + 1 = 81 ( subtract 1 from both sides )

x² = 80 ( take square root of both sides )

x = \sqrt{80} = \sqrt{16(5)} = \sqrt{16} × \sqrt{5} = 4\sqrt{5}

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