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STALIN [3.7K]
2 years ago
7

Pls helpp! asap

Mathematics
1 answer:
Setler79 [48]2 years ago
4 0

The length of the side between the vertices A′ and B′ is 16/7 units.

<h3>Transformation</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are<em> reflection, translation, rotation and dilation.</em>

Dilation is the increase or decrease in the size of a figure by a factor k. If a figure is dilated to produce an image, they are similar, hence the ratio of the corresponding sides are proportional.

\frac{A'B'}{AB} =\frac{C'D'}{CD} \\&#10;\\&#10;\frac{A'B'}{4}=\frac{8}{14}  \\&#10;\\&#10;A'B'=\frac{16}{7}

The length of the side between the vertices A′ and B′ is 16/7 units.

Find out more on transformation at: brainly.com/question/1548871

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Graph the line with slope <br> 3/4<br><br><br> passing through the point (1,4)<br><br><br> .
Valentin [98]

To graph the line, we must first find out the equation for the line in slope-intercept form (y = mx + b). So far, we only have the slope, so the line's equation is y = 3/4x + b. But, by inserting the values of x and y in the point we know, we can find the y - intercept.


4 = 3/4 + b


b = 13/4


That means that the equation of our line is y = 3/4x + 13/4. Now we can graph. But, there is another way to go about (slightly faster too). Since we know the coordinates of 1 point, we can put that line down. Then, since we know that slope is rise over run, we can say, that with a slope of 3/4, one would go 3 points up for every 4 to the right. Now we can go 3 points up and 4 points to the right of point (1,4). That would be (5, 7). Now we can graph (since we have 2 points, or an equation).


The graph looks like this:



3 0
3 years ago
The radius of a circle is 13miles. what is the area of a sector bounded by a 20 degree arc
Stolb23 [73]

Answer:

Area of the sector = 29.48 square miles.

Step-by-step explanation:

Given:

Radius of a circle = 13 miles

Angle bounded by the arc = 20 deg

To find

Area of the sector bounded by 20 degrees.

Note: Area of a sector = \frac{(\theta)}{360}\times \pi\times r^2

Plugging the values in the equation.

⇒ \frac{(\theta)}{360}\times \pi\times r^2

⇒ (\frac{20}{360})\times  3.14\times 13^2

⇒ 29.48 square-miles

So the area of the sector bounded by 20 degree arc is 29.48 square miles.

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3 years ago
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belka [17]
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ale4655 [162]
1675/3890 you are dividing 1675 by 3890 so it equals 0.43059...=0.4 simplified to the first decimal
3 0
2 years ago
Read 2 more answers
#1 #2 #3 &amp; #4 thank you
lubasha [3.4K]
I only (sort of) know 3 and 4

3. Andle 1 is an example of an angle bigger than
{90}^{o} c
I don't know what you call it.

4. If you have a straight line, both angles (or more) added up need to be
{180}^{o} c
so if angle 1 is 129, 180-129=51
angle 2 is
{51}^{o} c

If 1 is what is the relationship between the two angles, then maybe the answer is that they both added up need to be 180 degress (?)

And 2 is probably the same as 3 but with angle 2, angle two is an example of an angle smaller than 90 degrees
6 0
3 years ago
Read 2 more answers
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