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alisha [4.7K]
3 years ago
13

In the past you paid $800$800 per month to rent your apartment. You now pay $900$900 per month for your rent. What is the percen

t increase in your rent?
Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0
The persent increase is 200%
Iteru [2.4K]3 years ago
3 0
Calculate the rent increase:  It's $900-$800 = $100.

Now divide this increase by the original rent:

$100
------- = 1/8, or 0.125.
$800

Mult. this by 100%, we get 12.5% (answer)
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Write 3.6 in a word form
Anit [1.1K]
Three and six tenths

Hope I helped!
5 0
3 years ago
The equation (x + 6)^2 + (y + 4)^2 = 36 models the position and range of the source of a radio signal. Describe the position of
ElenaW [278]
A circle equation is :
( x - p )² + ( y - q )² = r², where p and q are coordinates of the center.
The position of the source is : ( - 6, - 4 ) and the range :
r² = 36   ⇒   r = 6
3 0
3 years ago
Read 2 more answers
This is the answer right?
dalvyx [7]
No, the question is stating the product of a number (the variable n represents the number) and 10 is 142. In other words, 10 times another number is 142. Hence, the answer would be A.
5 0
3 years ago
Identify the x-intercepts of the function below f(x)=x^2+12x+24
damaskus [11]

<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here, for (1) a = 1, b= 12 and c = 24

X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

8 0
3 years ago
Please help ASAP!!! 34 points!
vladimir2022 [97]
The answer would be B y=1/2x-1
7 0
3 years ago
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