There is a box labeled * Less Cash Received in the deposit ticket. The number in this box would be the amount of cash Vera received.
The number in this box is 80.00.
Vera received $80.00
Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Answer:
10
Step-by-step explanation:
The y-intercept for each line is...
y=2x+7 (0, 7)
y=2x-3 (0, -3)
Note this is because...
y=mx+b
b represents the y-intercept
Using the distance formula...






The question is incomplete:
James has dimes and quarters saved up in his change jar. He has a total of 162 coins totaling $31.20 what is the total amount james has in quarters?
a. $10.00
b. $6.20
c.$15.50
d.$25.00
Answer:
d.$25.00
Step-by-step explanation:
With the information provided, you can write the following equations given that dimes are equal to 0.10 and quarters to 0.25 to determine the number of dimes and quarters that James has:
x+y=162 (1)
0.10x+0.25y=31.20 (2), where:
x is the number of dimes
y is the number of quarters
First, you can solve for x in (1):
x=162-y (3)
Then, you have to replace (3) in (2) and solve for y:
0.10(162-y)+0.25y=31.20
16.2-0.10y+0.25y=31.20
0.15y=31.20-16.2
0.15y=15
y=15/0.15
y=100
Finally, you have to replace the value of y in (3) to find x:
x=162-100
x=62
Now, you know that James has 100 quarters and you can multiply this number for the value of a quarter to find the amount James has in quarters:
100*0.25=25
According to this, the answer is that James has $25 in quarters.