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amm1812
3 years ago
5

Plot the following wing points on a number line 2/3, 1/6 & 4/10

Mathematics
1 answer:
V125BC [204]3 years ago
5 0
1/6 then 4/10 then 2/3
You might be interested in
4. You want to know if there's an association between college students' spring break destinations and what year they're in. You
Pachacha [2.7K]

Answer:

\chi^2 =27.356

p_v = P(\chi^2_{9} >27.356)=0.00122

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(27.356,9,TRUE)"

Since the p value is lower than the significance level assumed 0.05 we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                           Amusement Parks     Mexico    Home    Other    Total

Freshman                     23                         21            43          21         108

Sophomore                  34                         23            14          26        97

Junior                           25                         30            23         26        104

Senior                           27                         33             17         19         96

Total                            109                        107            97         92        405

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the two random variables

H1: There is dependence between the two variables

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{109*108}{405}=29.07

E_{2} =\frac{107*108}{405}=28.53

E_{3} =\frac{97*108}{405}=25.87

E_{4} =\frac{92*108}{405}=24.53

E_{5} =\frac{109*97}{405}=26.11

E_{6} =\frac{107*97}{405}=25.63

E_{7} =\frac{97*97}{405}=23.23

E_{8} =\frac{92*97}{405}=22.03

E_{9} =\frac{109*104}{405}=27.99

E_{10} =\frac{107*104}{405}=27.48

E_{11} =\frac{97*104}{405}=24.91

E_{12} =\frac{92*104}{405}=23.62

E_{13} =\frac{109*96}{405}=25.84

E_{14} =\frac{107*96}{405}=25.36

E_{15} =\frac{97*96}{405}=22.99

E_{16} =\frac{92*96}{405}=21.81

And the expected values are given by:

                        Amusement Parks     Mexico    Home    Other    Total

Freshman                   29.07                28.53     25.87     24.53      108

Sophomore                26.11                  25.63     23.23     22.03      97

Junior                         27.99                 27.48     24.91      23.62     104

Senior                        25.84                 25.36     22.99      21.81       96

Total                            109                      107         97           92         405

And now we can calculate the statistic:

\chi^2 =27.356

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(4-1)(4-1)=9

And we can calculate the p value given by:

p_v = P(\chi^2_{9} >27.356)=0.00122

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(27.356,9,TRUE)"

Since the p value is lower than the significance level assumed 0.05 we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

7 0
3 years ago
An alpine area of a national park near a trail is normally covered by plants, but much of the area is now bare soil. Park ranger
Ira Lisetskai [31]

Answer:

The correct option is;

comparing plant survivorship in areas where hikers stay on the trail with plants where hikers leave the trail

Step-by-step explanation:

The hypothesis that the area formerly covered by known plants which is now bare soil due to trampling in the alpine areas by hikers can be tested by means of comparing the areas where during the cause of their visit, the hikers remain on the trail as they move within the park to other portion of the park where it is known that there are either very few or no hiker remain on the trail. The outcome will determine if the cause of the appearance of bare soil is due to the transit and trampling by hikers.

8 0
3 years ago
What is the simplest form of 2 sq root 3/ sq root 6
Shkiper50 [21]

Answer:

2/√2

Step-by-step explanation:

We are to solve this surd question

2(√3)/√6

2(√3)/√2×3

2(√3)/√2×√3

Divide both by√3

2/√2

We will have to leave the answer in surd form

So the final answer is 2/√2

8 0
3 years ago
Which list shows all the factors of 36?
almond37 [142]

Answer:

1,2,3,4,6,9,12,18,36 Is correct one

8 0
3 years ago
Read 2 more answers
an elephant at the zoo lost 24 pounds over 6 months. The elephant lost the same amount of weight each month. Write an integer th
Viefleur [7K]


The elephant lost 4 pounds each month. Because he is losing weight, and not gaining weight, you have to make the answer negative
3 0
3 years ago
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