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LenaWriter [7]
3 years ago
13

x + 3y = 7 x - 3y = 1 Solve the system of equations. A) x = 4, y = 1 B) x = 1, y = 4 C) x = - 2 3 , y = 3 D) x = 3, y = - 2 3

Mathematics
2 answers:
Alik [6]3 years ago
6 0
X+3y=7
x-3y=1
add them together

x+3y=7
<u>x-3y=1 +
</u>2x+0y=8

2x=8
divide 2
x=4
subsitute
x+3y=7
4+3y=7
subtract 4
3y=3
divid 3
y=1

x=4
y=1

answer is A
<u />
Bumek [7]3 years ago
6 0
X + 3y = 7 
<span>x - 3y = 1

x + 3y = 7
   - 3y    -3y

x = 7 - 3y

</span><span>x - 3y = 1
</span>7 - 3y - 3y = 1
7 -6y = 1
-7         -7

-6y = -6
y = 1

Now solve for x
<span>
X + 3y = 7
</span>x + 3 = 7
x = 4

Now we have our values:-
x = 4 and y = 1

Answer: <span>A) x = 4, y = 1</span>
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1) The solution for m² - 5m - 14 = 0 are x=7 and x=-2.

2)The solution for b² - 4b + 4 = 0 is x=2.

<u>Step-by-step explanation</u>:

The general form of quadratic equation is ax²+bx+c = 0

where

  • a is the coefficient of x².
  • b is the coefficient of x.
  • c is the constant term.

<u>To find the roots :</u>

  • Sum of the roots = b
  • Product of the roots = c

1) The given quadratic equation is m² - 5m - 14 = 0.

From the above equation, it can be determined that b = -5 and c = -14

The roots are -7 and 2.

  • Sum of the roots = -7+2 = -5
  • Product of the roots = -7\times2 = -14

The solution is given by (x-7) (x+2) = 0.

Therefore, the solutions are x=7 and x= -2.

2) The given quadratic equation is b² - 4b + 4 = 0.

From the above equation, it can be determined that b = -4 and c = 4

The roots are -2 and -2.

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The solution is given by (x-2) (x-2) = 0.

Therefore, the solution is x=2.

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