It would be t=0.8, mainly bc you subtract two from six , that reduces it to four
then you divide four by five and it should give you your answer
and to chack your work put .8 where t was and solve
the number would be 14.
in order for you to figure this out you divide.
42/3=14 and
14 * 3 = 42
hope this helps.
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:
The y coordinate is 6 and the x coordinate is 4
I hope this helps!
Answer:
1,2,3
18=8×1 =
Step-by-step explanation:
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