Three vertices of a rectangle have coordinates (–6, 2), (–6,–1), and (4, 2).
1 answer:
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This can be solved by factoring.
First, set the expression equal to zero.
Then, find two the factors of
whose sum is 
.
Split into these two factors.
Next, factor by grouping.
By the Zero Product Property, set each factor equal to zero.
These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree
has exactly complex roots, but real roots are also complex roots. That sounds confusing, but this just means that you're done. Your answers are -2 and 1/3. There are two real roots.
First, set the expression equal to zero.
Then, find two the factors of
Split
Next, factor by grouping.
By the Zero Product Property, set each factor equal to zero.
These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree
Answer:
A.
Step-by-step explanation:
To find f(-2) in f(x)=5*3^x, plug in -2 into all the x values.
f(-2)=5*3^-2, you can use calculator to calculate 3^-2 which equals 0.1, forever 1's.
f(-2)=5*0.1=0.5 Forever 5's.
f(-2)=0.5 or
Hope this helps!
If not, I am sorry.