All categories

3 years ago

two crates contain Apple's, pears and oranges. there are 184 apples and pears in crate one and 248 apples and oranges in the sec

ond crate. there are 3 times as many oranges as pears. how many apples are there altogether?

Mathematics

1 answer:

netineya [11]3 years ago

6 0

$184 + 248 \div 3 =$

You might be interested in

Y + 1 = -2x-3 in standard form *

notka56 [123]

Answer:

y = -2x - 4

Step-by-step explanation:

y + 1 = -2x - 3

Subtract 1 from both sides to get the y by itself

y = -2x - 3 - 1

Simplify (Combine Like terms)

y = -2x - 4

8 0

3 years ago

6. If m∠COD=8x+13, m∠BOC=3x-10, and m∠BOD=12x-6, find m∠BOD

Ahat [919]

Answer:

Step-by-step explanation:

Given

m∠COD=8x+13,

m∠BOC=3x-10, and

m∠BOD=12x-6

The following addition property is true;

<BOD = <BOC + <COD

Substitute

12x-6 = 3x-10+8x+13

12x-6 = 11x+3

12x-11x = 3+6

x = 9

Get <BOD

<BOD = 12x-6

<BOD = 12(9)-6

<BOD = 108-6

<BOD = 102°

4 0

3 years ago

Earl needs to fill up juice cups for his little brothers birthday party. There are 25 juice cups and each holds 12 fluid ounces.

Blizzard [7]

It would take 3 bottles. 25 twelve-ounce cups equals out to 300 ounces. There is only 128 ounces in a gallon.

8 0

3 years ago

Read 2 more answers

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

Solve the equation for x. show each step of the solution. name the justifications for each step of the solutions.

UkoKoshka [18]

Answer:

What grade is this?

Step-by-step explanation:

7 0

3 years ago