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3 years ago

How many times does four go into 153 ? What Is the remainder ?

Mathematics

2 answers:

Cloud [144]3 years ago

6 0

153 goes into 4 38 and the remainder is 1.

Vlada [557]3 years ago

4 0

Basically your question is asking for $\frac{153}{4}$

So if we divide it, we get 38.25

That .25 means it had a remainder of 1, because 1/4 = .25

<u>So it has a remainder of 1 and 4 goes into it 38 times.</u>

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Indicate which formula you would use to solve for the missing side B and then write your answer correct to two decimal places.Wr

agasfer [191]

Answer:

The measure of the angle $b$ is approximately 44.040°.

Step-by-step explanation:

We need to apply Law of the Sine to determine the value of angle $b$ , since the length of the side opposite to this side and another side length and its opposite angle are known. That is:

$\frac{3.6}{\sin b} = \frac{5.1}{\sin 100^{\circ}}$

$\sin b = \frac{3.6}{5.1}\times \sin 100^{\circ}$

$b = \sin^{-1}\left(\frac{3.6}{5.1}\times \sin 100^{\circ} \right)$

$b \approx 44.040^{\circ}$

The measure of the angle $b$ is approximately 44.040°.

4 0

3 years ago

Need help thank you !

USPshnik [31]

Answer)
Exact form - 101/15
Decimal form - 6.73
Mixed number - 6 11/15

6 0

2 years ago

Read 2 more answers

Please help me ASAP !!

Nadya [2.5K]

Answer:

Step-by-step explanation:

<1+<2=90 complementary

<1=4 times <2

X+4x=90

5x=90

X=18

<1=18×4=72 degrees

<2=18 degrees

<1=<3 because they are vertical

Do <3= 72

<3+<4=180 because they are supplementary

72+<4=180

<4=108 degrees

<3=72 degrees

4 0

3 years ago

Simplify<br><br> b - 3 + 6 - 2b

Mariulka [41]

Answer:

-b+3

Step-by-step explanation:

B-2b=-b

-3+6=3

8 0

2 years ago

Read 2 more answers

"There are 15 questions on an exam. In how many ways can the exam be answered with exactly 8 answers correct?"

erastovalidia [21]

Answer:

The exam can be answered with exactly 8 answers correct in 6435 ways.

Step-by-step explanation:

The order is not important.

For example, answering correctly the questions 1,2,3,4,5,6,7,8 is the same outcome as answering 2,1,3,4,5,6,7,8. So we use the combinations formula to solve this problem.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

"There are 15 questions on an exam. In how many ways can the exam be answered with exactly 8 answers correct?"

Combinations of 8 questions from a set of 15. So

$C_{15,8} = \frac{15!}{8!(15-8)!} = 6435$

The exam can be answered with exactly 8 answers correct in 6435 ways.

5 0

3 years ago