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NeX [460]
3 years ago
11

Explain the difference between (-5)2 and -5)2

Mathematics
1 answer:
kirza4 [7]3 years ago
4 0

Answer:

There is no difference ???

Step-by-step explanation:

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70,00 Is the the answer
7 0
3 years ago
Solve 7 ( x + 1 ) + 2 = 5x + 15
yawa3891 [41]

Answer:

x = 3

Step-by-step explanation:

7(x + 1) + 2 = 5x + 15

~Simplify left side

7x + 7 + 2 = 5x + 15

~Combine like terms

7x + 9 = 5x + 15

~Subtract 9 to both sides

7x = 5x + 6

~Subtract 5x to both sides

2x = 6

~Divide 2 to both sides

x = 3

Best of Luck!

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3 years ago
Can anyone help me find the area of these two pls ? ty
NNADVOKAT [17]
Equation pi X r^2 first one = 158.37
second one 50.27
8 0
3 years ago
Sally bought some candy bars for $1.25 each and some sodas for $1.49 each. If she bought a total of 38 items and spent $50.38 ho
hammer [34]

Answer:

26 candy bars and 12 sodas

Step-by-step explanation:

This problem can be solved by a simple system of equations

I am going to call x the number of candy bars that Sally bought and y the number of sodas that Sally bought.

The fact that she bought 38 itens means the x + y = 38.

She spent $50.38. The value she spent is the sum of the number of candy bars multplied by the value of the candy bar and the number of sodas multiplied by value of a soda. So 1.25x + 1.49y = 50.38

So we have to solve the following system:

1)x + y = 38

2)1.25x + 1.49y = 50.38

From 1), we have that x = 38 - y. I am going to replace it in 2)

1.25(38-y) + 1.49y = 50.38

-1.25y + 1.49y = 50.38 - 47.5

0.24y = 2.88

y = 12.

Sally bought 12 sodas.

In 1: x = 38-y = 38-12 = 26

Sally bourght 26 candy bars

6 0
3 years ago
Read 2 more answers
A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 42 lik
Step2247 [10]

Answer:

Step-by-step explanation:

Universal set

U = 500

The number that likes snickers

n(S) = 42

The number that like Twix.

n(T) = 110

The number that like Reeses

n(R) = 125

n(S n T) = 33

n(T n R) = 62

n(S n R) = 26

n( S n R n T) = 22

Then,

n(S n T) only = n(S n T) - n(S n R n T)

n(S n T) only =33 - 22 = 11

n(T n R) only = n(T n R) - n(S n R n T)

n(T n R) only =62 - 22 = 40

n(S n R) only = n(S n R) - n(S n R n T)

n(S n R) only =26 - 22 = 4.

Also,

n(S) only = n(S) - n(S n R) - n(S n T) only

n(S) only = 42 - 26 - 11 = 5

n(T) only = n(T) - n(T n R) - n(T n S) only

n(T) only = 110 - 62 - 11 = 37

n(R) only = n(R) - n(S n R) - n(R n T) only

n(R) only = 124 - 26 - 40 = 58

Then, to know if some student don't like any of the of chocolate,

Let know the number of students that like the chocolate candy

n(S) + n(T)only + n(T n R)only + n(R) only

42 + 37 + 40 + 58 = 177 students.

Therefore, the total students that like chocolate candy is 177, so those  that does not like any of them are

n(S U R U T)' = U – n(S U R U T)

n(S U R U T) = 500 - 177 = 323.

So, the question is how many student likes at most 2 kinds of these chocolates, this means that they can like exactly 2 or less or even none.

So, this category are

n(2 most) = n(S n T)only + n(R n T)only + n(S n R)only + n(s)only + n(T)only + n(R)only + n(S U R U T)'

n(2 most) = 11 + 40 + 4 + 5 + 37 + 58 + 323

n(2 most) = 478

The correct answer is E.

Check attachment for Venn diagram

5 0
3 years ago
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