Answer:
and 
Step-by-step explanation:
sinB = 
= 
=
tanC = 
= 
= 
Thus
sinB tanC = × ( cancel b on numerator/ denominator )
=
---------------------------------------------------------------------------
sinC = = 
=
tanB = = 
= 
Thus
sinC tanB = × ( cancel c on numerator/ denominator )
=
To solve this problem you must apply the procceddure shown below:
1. You have the following system of equations:
<span>
x+y = 3
2x–y = 6
2. Then, you must clear the variable y from the first equation and susbtitute it into the second equation, as below:
x+y=3
y=3-x
2x-y=6
2x-(3-x)=6
2x-3+x=6
3x=6+3
3x=9
3. Therefore, the value of x is:
x=9/3
x=3
4. As you can see, the correct answer is:
x=9
</span>
The x intercept occurs when y = 0.
0=(x+2)^2 - 1
1=(x+2)^2
Take the square root of both sides. Note that the sqrt of 1 is 1. Then solve for x.
1=x+2
-1=x
The x intercept is -1.
The y intercept occurs when x=0.
y=(0+2)^2 - 1
y=2^2 -1
y=4-1
y=3
The y intercept is 3.
Now, to find the vertex...
This parabola is currently in a format called the vertex form, which is:
f(x) = (x-h)^2 + k
where (h, k) is the vertex.
Therefore, the vertex is (-2, -1).
Answer: -7b² + 2b - 8
Step-by-step explanation:
<u>Given expression</u>
3 - b (7b + 2) + 3b - (11 - b)
<u>Expand parentheses and apply the distributive property if necessary</u>
=3 - b · 7b - b · 2 + 3b - 11 + b
=3 - 7b² - 2b + 3b - 11 + b
<u>Combine like terms</u>
=-7b² + (3b - 2b + b) + (3 - 11)
=
Hope this helps!! :)
Please let me know if you have any questions
16x^2 + 25y^2 + 160x - 200y + 400 = 0 Rearrange and regroup.
(16x^2 + 160x) + (25y^2 - 200y ) = 0-400. Group the xs together and the ys together.
16(X^2 + 10x) + 25(y^2-8y) = -400. Factorising.
We are going to use completing the square method.
Coefficient of x in the first expression = 10.
Half of it = 1/2 * 10 = 5. (Note this value)
Square it = 5^2 = 25. (Note this value)
Coefficient of y in the second expression = -8.
Half of it = 1/2 * -8 = -4. (Note this value)
Square it = (-4)^2 = 16. (Note this value)
We are going to carry out a manipulation of completing the square with the values
25 and 16. By adding and substracting it.
16(X^2 + 10x) + 25(y^2-8y) = -400
16(X^2 + 10x + 25 -25) + 25(y^2-8y + 16 -16) = -400
Note that +25 - 25 = 0. +16 -16 = 0. So the equation is not altered.
16(X^2 + 10x + 25) -16(25) + 25(y^2-8y + 16) -25(16) = -400
16(X^2 + 10x + 25) + 25(y^2-8y + 16) = -400 +16(25) + 25(16) Transferring the terms -16(25) and -25(16)
to other side of equation. And 16*25 = 400
16(X^2 + 10x + 25) + 25(y^2-8y + 16) = 25(16)
16(X^2 + 10x + 25) + 25(y^2-8y + 16) = 400
We now complete the square by using the value when coefficient was halved.
16(x-5)^2 + 25(y-4)^2 = 400
Divide both sides of the equation by 400
(16(x-5)^2)/400 + (25(y-4)^2)/400 = 400/400 Note also that, 16*25 = 400.
((x-5)^2)/25 + ((y-4)^2)/16 = 1
((x-5)^2)/(5^2) + ((y-4)^2)/(4^2) = 1
Comparing to the general format of an ellipse.
((x-h)^2)/(a^2) + ((y-k)^2)/(b^2) = 1
Coordinates of the center = (h,k).
Comparing with above (x-5) = (x - h) , h = 5.
Comparing with above (y-k) = (y - k) , k = 4.
Therefore center = (h,k) = (5,4).
Sorry the answer came a little late. Cheers.
