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tester [92]
3 years ago
14

What is a three letter word used to show division in a word problem?

Mathematics
2 answers:
olasank [31]3 years ago
6 0
A three-letter word used to show division in a word problem is PER.
vichka [17]3 years ago
3 0

A three-lettered word in a word problem that indicates division is *PER*

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3/5 x 10= 6 miles because coach runs 10 times what you run
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Graph y=-3x +7 and the line that is<br> parallel to it that passes through (4,1).
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Y = -3x + 13

Steps and the graph are on paper

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The answer to the question provided is letter D.

8 0
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the graph shows the speed of a vehicle during the final 50 seconds of a journey at the start of the 50 seconds the speed is k me
Simora [160]

Answer:

a) 27 m/s

b) 30 m/s

c)   i) 3

     ii) Deceleration

Step-by-step explanation:

The question is not complete, the correct question is given as:

The graph shows information about the speed of a vehicle during the final 50 seconds of a journey.  At the start of the 50 seconds the speed is k metres per second.  The distance travelled during the 50 seconds is 1.35 kilometres.

(a) Work out the average speed of the vehicle during the 50 seconds

(b) Work out the value of k.

(c) (i) Calculate the gradient of the graph in the final 10 seconds of the journey

    (ii) Describe what this gradient represents

Answer:

The graph is attached. The total time = 50 seconds, total distance = 1.35 km = 1350 m  

a) The average speed is the ratio of the total distance traveled to the total time taken to cover this distance. The average speed is given by the formula:

Average \ speed=\frac{total\ distance}{total\ time}\\ Substituting: \\ Average \ speed=\frac{1350\ m}{50\ s} = 27\ m/s

b) From the graph, the total distance covered is the area of the graph. The graph is made up of a rectangle and triangle, the area of the graph is equal to the sum of area of rectangle and area of triangle.

Total \ distance=Total\ area=Area\ of \ rectangle+Area\ of \ triangle\\Total \ distance=(length *breadth)+\frac{1}{2}base*height\\1350 \ m=(40*k)+0.5*10*k\\1350=40k+5k\\45k=1350\\k=1350/45\\k=30\ m/sc) i) The gradient in the last 10 seconds is the ratio of change in speed to change in time

Gradient=\frac{change\ in\ speed }{change\ in\ time}=\frac{0-k}{50-40}  \\ bt \ k=30\\Gradient=\frac{0-30}{50-40}= \frac{-30}{10} =-3

ii) Since the gradient is negative it means it is deceleration. That is in the in the last 10 seconds the vehicle decelerates at a rate of 3 m/s²

6 0
3 years ago
Which point is on a line that passes through point R and is perpendicular to line PQ?
aliya0001 [1]
Your answer would be (-4,-8)
5 0
3 years ago
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